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irinina [24]
2 years ago
14

Why is important to maintain an assessment’s validity, reliability, and equity in testing?

Mathematics
2 answers:
guapka [62]2 years ago
7 0

Answer:

because it refers to the degree to which a resulting score can be used to make meaningful and useful inferences about the test taker.

Step-by-step explanation:

hope this helps

plz mark brainliest

Greeley [361]2 years ago
6 0
Why is important to maintain an assessment’s validity, reliability, and equity in testing?

Answer: Reliability refers to the degree to which scores from a particular test are consistent from one use of the test to the next. ... Ultimately then, validity is of paramount importance because it refers to the degree to which a resulting score can be used to make meaningful and useful inferences about the test taker
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WILL MAKE BRAINLIEST!!! <br> Match the correct scale factor to each dilation.<br> Solve for a and b
White raven [17]

Answer:

I am having a hard time reading the letters, so I hope this makes sense.  I think that the numbers for the top triangles is given is 6 and 3.  That means that the scale factor from the little to the big is 2 and from the big to the little is 1/2.  It is the same for the bottom triangles.

Step-by-step explanation:

If the triangles are similar the scale factors will be the same for all three corresponding sides of the triangle.  You find the two sides that are corresponding and ask yourself what do I have to multiple the side of of triangle to get the new triangle.  

If one side is 3 and the other triangles side is 6.  I am asking myself what do I have to multiple 3 by to get 6?  2.  That is my scale factor.

3x = 6

x = 2

The scale factors are always reciprocals of each other.  If I go the other direction I can write the equation

6x = 3 and when I divide both sides by 6, I get a scale factor of 1/2.

The bottom triangles:

2.5 x = 5

x = 2

and

5x = 2.5

x =1/2

4 0
2 years ago
What is the equation of the line that passes through the point ( − 3 , 1 )and has a slope of 2/3
andrezito [222]

Answer: y = 2/3x + 3

Step-by-step explanation:

We will write the equation in slope intercept form (y=mx+b).

In the formula y=mx + b,  m is the slope and b is the y intercept. We need the slope and y intercept numbers to write the equation. Since we know the slope we will use the given point to find the y intercept by plotting in the x and y coordinates into the formula.

1 = 2/3(-3) + b       Solve for b

1= -6/3 + b

1 = -2 + b  

+2   +2

b = 3  

The equation will be   y = 2/3x + 3

3 0
3 years ago
How do you decide whether substitution is the best method to solve a system in three variables?
Ivan
<span>Select one equation and solve it for one of its variables.
In the other equation, substitute for the variable just solved.
Solve the new equation. 
<span>Substitute the value found into any equation involving both variables and solve for the other variable. </span></span>
3 0
3 years ago
Use chain rule to find dw/dt w=ln(x^2 + y^2 + z^2)^(1/2) , x=sint, y=cost, z=tant
son4ous [18]
The chain rule states that

\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\partial w}{\partial x}\dfrac{\mathrm dx}{\mathrm dt}+\dfrac{\partial w}{\partial y}\dfrac{\mathrm dy}{\mathrm dt}+\dfrac{\partial w}{\partial z}\dfrac{\mathrm dz}{\mathrm dt}

Since \ln(x^2+y^2+z^2)^{1/2}=\dfrac12\ln(x^2+y^2+z^2), you have

\dfrac{\partial w}{\partial x}=\dfrac x{x^2+y^2+z^2}
\dfrac{\partial w}{\partial x}=\dfrac y{x^2+y^2+z^2}
\dfrac{\partial w}{\partial z}=\dfrac z{x^2+y^2+z^2}

and

\dfrac{\mathrm dx}{\mathrm dt}=\cos t
\dfrac{\mathrm dy}{\mathrm dt}=-\sin t
\dfrac{\mathrm dz}{\mathrm dt}=\sec^2t

Also, since x^2+y^2+z^2=\sin^2t+\cos^2t+\tan^2t=1+\tan^2t=\sec^2t, the derivative is

\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\sin t\cos t}{\sec^2t}-\dfrac{\sin t\cos t}{\sec^2t}+\dfrac{\tan t\sec^2t}{\sec^2t}
\dfrac{\mathrm dw}{\mathrm dt}=\tan t
4 0
3 years ago
In Circle O, centrally angle AOB measures π/3 radians.What is the length of arc AB?
Oksanka [162]

Answer:

s=r*\pi /3

Step-by-step explanation:

The length of any arc is calculated using the following equation:

s = r*θ

Where s is the length of the arc, r is the radius of the circle and θ is the angle in radians.

So, if we have a Circle O and a centrally angle AOB that measures π/3 radians, the value of the length of arc AB is calculated as:

s=r*\pi /3

Where r is the radius of the circle O.

5 0
3 years ago
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