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3 years ago

The value of the _____ determines whether the graph of an exponential function increases or decreases from left to right.

2 answers:

7 0

The value of the exponential function determines weather the graph of an exponential function increases or decreases from left to right.

kvasek [131]3 years ago

7 0

Answer:

The missing expression is 'b'.

Step-by-step explanation:

We have been given an incomplete sentence. We are supposed to fill in the given blank.

Sentence:

The value of the _____ determines whether the graph of an exponential function increases or decreases from left to right.

We know that an exponential function is in form $y=a\cdot b^x$ , where,

a = Initial value,

b = For growth $b>1$ and for decay $b$ .

Therefore, the value of 'b' determines whether the graph of an exponential function increases or decreases from left to right.

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C, G, and D are collinear. E, G, and F are also collinear. The two lines

Elodia [21]

Answer:

EG is 19 units

Step-by-step explanation:

Let us solve the question

∵ Lines CD and EF intersected at point G

∴ CD = CG + GD

∴ EF = EG + GF

∵ Line EF bisects line CD

→ That means G is the midpoint of CD

∴ CG = GD

∵ CG = 5x -1

∵ GD = 7x - 13

→ Equate them to find x

∴ 7x - 13 = 5x -1

→ Add 13 to both sides

∴ 7x -13 + 13 = 5x - 1 + 13

∴ 7x = 5x + 12

→ Subtract 5x from both sides

∴ 7x - 5x = 5x - 5x + 12

∴ 2x = 12

→ Divide both sides by 2

∴ $\frac{2x}{2}=\frac{12}{2}$

∴ x = 6

∵ EF = 6x - 4

→ Substitute x by 6 to find its length

∴ EF = 6(6) - 4 = 36 - 4

∴ EF = 32

∵ EF = EG + GF

∵ GF = 13

∴ 32 = EG + 13

→ Subtract 13 from both sides

∵ 32 - 13 = EG + 13 - 13

∴ 19 = EG

∴ EG = 19 units

7 0

3 years ago

Six stand-up comics, A, B, C, D, E, and F, are to perform on a single evening at a comedy club. The order of performance is

kiruha [24]

Answer:

a) 1/6

b) 1/36

c) 1/720

d) 1/3

Step-by-step explanation:

a) Any of the six comics can perform in the fourth place, so there is one chance in six that Comic F is the one that performs fourth.

$P(F=4th)=1/6$

b) In this case, we have two conditions. Both are independent of each other, so the probability of both happening is the product of the probabilities of each happening individually:

$P(D=4th \&B=2nd)=P(D=4th)\cdot P(B=2nd)=(1/6)\cdot(1/6)=1/36$

c) This combination is one in all possible orders of perform. The amount of combinations of orders is n!=6!=720 possible combinations. So the probability of this specific order is:

$P(F, D, B, A, C, E)=1/720$

d) In this case, of the six possible comics performing in the last place, we calculate the probability of 2 of them being in that place. So the probability is:

$P(C=6th\,or\, E=6th)=2/6=1/3$