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2 years ago

The value of the _____ determines whether the graph of an exponential function increases or decreases from left to right.

2 answers:

7 0

The value of the exponential function determines weather the graph of an exponential function increases or decreases from left to right.

kvasek [131]2 years ago

7 0

Answer:

The missing expression is 'b'.

Step-by-step explanation:

We have been given an incomplete sentence. We are supposed to fill in the given blank.

Sentence:

The value of the _____ determines whether the graph of an exponential function increases or decreases from left to right.

We know that an exponential function is in form $y=a\cdot b^x$ , where,

a = Initial value,

b = For growth $b>1$ and for decay $b$ .

Therefore, the value of 'b' determines whether the graph of an exponential function increases or decreases from left to right.

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Please help! Need answer ASAP!

REY [17]

ANSWER:

A ) It also increases.

EXPLANATION:

When the measure of angle A increases im the trianes, the measure of angle A on line p also increases. This is angle A in the triangle and angle A on line p are equivalent to each other. Hence, if there is an increase to one of the angle As then there is also an increase to the other.

Therefore, the answer must be:

A ) It also increases.

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2 years ago

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There are 4040 tables in a library, with 30%30% of them seating 44 people. The tables remaining only seat 22 people. How many se

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3 years ago

Let a, b, c, and d be real numbers with a, c 6= 0. Prove that the lines y = ax+b and y = cx + d have the same x-intercept if and

Monica [59]

Step-by-step explanation:

We have got the lines :

$y=ax+b\\y=cx+d$

Both lines intercept the x-axis in the point :

$I = (i_{1} ,i_{2})$

In all point from x-axis the y-component is equal to 0.

$I=(i_{1},o)$

We replace the I point in the lines equations:

$0=a(i_{1})+b \\0=c(i_{1})+d$

From the first equation :

$0=a(i_{1})+b \\-b=a(i_{1})\\i_{1}=\frac{-b}{a}$

From the second equation :

$0=c(i_{1})+d\\ -d=c(i_{1})\\i_{1}=\frac{-d}{c}$

Then $i_{1}=i_{1}$

Finally :

$\frac{-b}{a}=\frac{-d}{c} \\\frac{b}{a}=\frac{d}{c} \\ad=bc$

y = ax + b and y = cx + d have the same x-intercept ⇔ad=bc

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The 4th graph shows "inconsistent" equations.

The solution shown on the 5th graph is where the lines intersect, near point
(5, 3)

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3 years ago

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