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2 years ago

10

Problem and incorrect solution. Explanation of Errors Made. (Some have more than one mistake).in one box and then correct soluti

on (show all work) in another box. please help!!!

1 answer:

irga5000 [103]2 years ago

3 0

Answer:

In the second step, the +16 should be -16

In the 3rd step, you should add 16 instead of subtracting 16

m=0

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AB is perpendicular to line segment [CF, FH, DH, GH] . If the length of EF is a units, then the length of GH is [a, b, a+b, a-b]

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AB is perpendicular to [GH] and GH is [A]

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4 years ago

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The sale price of ground beef at a local grocery store is $1.49 for the first pound and $1.09 for each additional pound. Which f

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y=1.09x+0.4

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Let's assume that the price of beef stays the same for every pound of beef (the first pound is also $1.09)

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4 years ago

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3 years ago

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3 years ago

Three cards are dealt from a shuffled standard deck of playing cards. What is the probability that the three cards dealt are, in

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Answer:

The probability that the three cards dealt are, in order, an ace, a face card, and a 10 is $\frac{8}{5525}$

Step-by-step explanation:

Given : Three cards are dealt from a shuffled standard deck of playing cards.

To find : What is the probability that the three cards dealt are, in order, an ace, a face card, and a 10? (A face card is a jack, queen, or king.)

Solution :

Total number of cards - 52

Number of Ace = 4

Probability of getting an ace is $P_1=\frac{4}{52}$

Number of face cards = 12

Probability of getting a face card is $P_2=\frac{12}{51}$

Number of 10's = 4

Probability of getting a 10's is $P_3=\frac{4}{50}$

The probability that the three cards dealt are, in order, an ace, a face card, and a 10 is give by

$P=P_1\times P_2\times P_3$

$P=\frac{4}{52}\times \frac{12}{51}\times \frac{4}{50}$

$P=\frac{1}{13}\times \frac{12}{51}\times \frac{2}{25}$

$P=\frac{8}{5525}$

Therefore, The probability that the three cards dealt are, in order, an ace, a face card, and a 10 is $\frac{8}{5525}$

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3 years ago