I guess the chef is making the mixture for the sheriff... Let <em>x</em> be the amount of dressing with 5% vinegar that is required, and <em>y</em> the amount of 15% vinegar dressing (both amounts in mL).
The sheriff wants 390 mL of the mixed dressing, so that
<em>x</em> + <em>y</em> = 390
<em>x</em> mL of the 5% dressing contains 0.05<em>x</em> mL of vinegar, while <em>y</em> mL of the 15% dressing contains 0.15<em>y</em> mL of vinegar. The resulting mixture should have a concentration of 9% vinegar, so that it contains 0.09 (390 mL) = 35.1 mL of vinegar. This means
0.05<em>x</em> + 0.15<em>y</em> = 35.1
Solve for <em>x</em> and <em>y</em> :
<em>y</em> = 390 - <em>x</em>
0.05<em>x</em> + 0.15 (390 - <em>x</em>) = 35.1
0.05<em>x</em> + 58.5 - 0.15<em>x</em> = 35.1
23.4 = 0.10<em>x</em>
<em>x</em> = 234
<em>y</em> = 156
Answer:
6ft by 8ft
Step-by-step explanation:
1/4 inch = 1 ft
1 1/2 inches has six 1/4 inches
6 times 1 = 6ft
2 inches has eight 1/4 inches
8 times 1 - 8 ft
so its 6ft by 8ft
Answer: p = 6
Step-by-step explanation:
HI !
px + 3y - ( p-3)=0
a₁ = p , b₁ = 3 , c₁ = - (p-3)
=====================
12x + py - p=0
a₂ = 12 , b₂ = p , c₂ = -p
since , the equations have infinite solutions ,
a₁/a₂ = b₁/b₂ = c₁/c₂
p/12 = 3/p = p-3/p
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p/12 = 3/p
cross multiply ,
p² = 36
p = √36
p = 6
for the value of p = 6 , the equations will have infinitely many solutions
Answer:
The 99% confidence interval for the proportion of readers who would like more coverage of local news is (0.3685, 0.4315).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

99% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 99% confidence interval for the proportion of readers who would like more coverage of local news is (0.3685, 0.4315).