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Blizzard [7]
2 years ago
13

Karma is building a rectangular table with an area of 18,000 cm?. He wants to put wood trim around the four edges. What is the s

hortest length of trim he could use (nearest to hundredth)?​
Mathematics
1 answer:
jok3333 [9.3K]2 years ago
4 0

The shortest length is given by the function for the perimeter of the

rectangular table.

  • The shortest length of trim he could use is <u>536.66 cm</u>
<h3>Method used for finding the shortest length of trim</h3>

The given parameter;

Area of the rectangular table Karma is building, <em>A</em> = <u>18,000 cm²</u>

Required:

The shortest length of trim he could use which he wants to put around the four edges.

Solution:

Let <em>l</em> represent the length of the table, and let <em>w</em> represent the width, therefore;

Perimeter of the table, <em>P</em> = 2·l + 2·w

Area, <em>A</em> = l × w

Which gives;

18,000 = l × w

l = \dfrac{18,000}{w}

Which gives;

P = 2 \cdot \dfrac{18,000}{w} + 2 \cdot w

At the minimum point, we have;

\dfrac{d}{dw} P = \dfrac{d}{dw} \left(2 \cdot \dfrac{18,000}{w} + 2 \cdot w\right)= \mathbf{\dfrac{2 \cdot w^2 - 36,000}{w^2} }= 0

Which gives;

2·w² - 36,000 = w² × 0 = 0

2·w² = 36,000

w^2 = \dfrac{36,000}{2} = 18,000

The width of the rectangular table, <em>w</em> = √(18,000)

Length \ of \ the \ table\ l = \dfrac{18,000}{\sqrt{18,000} } = \sqrt{18,000}

Therefore;

The perimeter of the table, P ≈ 2 × √(18,000) + 2 × √(18,000) ≈ 536.656

The length of trim required = The perimeter of the rectangular table, <em>P</em>

Therefore;

  • The shortest length of the trim he could use, given to the nearest hundredth is <u>536.66 cm</u>

Learn more about area and perimeter of a figure here:

brainly.com/question/9135929

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