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dmitriy555 [2]
3 years ago
15

Inequalities! 20 Points!

Mathematics
2 answers:
Zanzabum3 years ago
7 0

Answer:

he needs at least 5800

5800/725

8

so he must sell at least 8 cars

There are only 45 cars on the lot, so that is the max he can sell

Choice C

8<=x<=45Step-by-step explanation:

il63 [147K]3 years ago
3 0

he needs at least 5800

5800/725

8

so he must sell at least 8 cars

There are only 45 cars on the lot, so that is the max he can sell

Choice C

8<=x<=45

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\displaystyle\bf\\\boxed{\bf sin\,y=x}\\\\2x^2+x-1=0\\\\x_{12}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{-1\pm\sqrt{1-4\cdot2\cdot(-1)}}{2\cdot2}=\\\\=\frac{-1\pm\sqrt{1+8}}{4}=\frac{-1\pm\sqrt{9}}{4}=\frac{-1\pm3}{4}\\\\x_1=\frac{-1+3}{4}=\frac{2}{4}=\boxed{\bf\frac{1}{2}}\\\\x_2=\frac{-1-3}{4}=\frac{-4}{4}=\boxed{\bf-1}\\\\sin\,y=\frac{1}{2}\\\\\boxed{\bf y_1=\frac{\pi}{6}~~or~~(30^o)}\\\\\boxed{\bf y_2=\frac{5\pi}{6}~~or~~(150^o)}\\\\sin\,y=-1\\\\\boxed{\bf y_3=\frac{3\pi}{2}~~or~~(270^o)}

 

 

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