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dmitriy555 [2]
3 years ago
15

Inequalities! 20 Points!

Mathematics
2 answers:
Zanzabum3 years ago
7 0

Answer:

he needs at least 5800

5800/725

8

so he must sell at least 8 cars

There are only 45 cars on the lot, so that is the max he can sell

Choice C

8<=x<=45Step-by-step explanation:

il63 [147K]3 years ago
3 0

he needs at least 5800

5800/725

8

so he must sell at least 8 cars

There are only 45 cars on the lot, so that is the max he can sell

Choice C

8<=x<=45

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<h3>Answer: LCM = 132</h3>

===================================================

Work Shown:

LCM = least common denominator

List out the prime factorization of each denominator

  • 6 = 2*3
  • 11 = 1*11
  • 12 = 2*2*3

So we have the list of primes 2,3, and 11 that help form the denominators when we multiply some of them together.

The prime 2 shows up at most twice, so 2*2 = 4 is a factor of the LCM

The prime 3 shows up at most one time, meaning 3 is also a factor

The prime 11 shows up at most one time, so 11 is another factor

Multiply these factors to get 4*3*11 = 12*11 = 132

The LCM is 132

---------------------

Another Approach:

Focus on 1/6 and 10/11 for now. The LCM is 66 because 6*11 = 66. We simply multiply the denominators together. Then we divide over the GCF 1 to get 66/1 = 66.

The LCM of 1/6 and 10/11 is 66

The fractions 1/6 and 10/11 are equivalent to 11/66 and 60/66 respectively

The original list of fractions updates to 11/66, 60/66, 5/12

We've gone from 3 different denominators to now 2 different denominators.

Repeat the steps of multiplying the denominators and dividing by the GCF

66*12 = 792

792/(gcf of 66 and 12) = 792/6 = 132

So the LCM of all the fractions is 132.

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