Answer:
There are 7,725 square feet of grass on the trapezoidal field
Step-by-step explanation:
Here in this question, we are interested in calculating the square feet of grass present on the trapezoidal field.
What this question is actually asking us is to calculate the area of the trapezoid-shaped grass field.
To calculate this area, what we need to do
simply is to use the formula for the area of a trapezoid.
Mathematically, the area of a trapezoid can be calculated using the formula;
Area of trapezoid = 1/2 * (a + b) * h
where a and b refers to the length of the parallel lengths of the trapezoid and h refers to the height of the trapezoid.
From the question;
a, b = 81ft and 125 ft
h = 75 ft
Substituting these values, we have :
Area = 1/2 * (81 + 125) * 75
Area = 1/2 * 206 * 75 = 83 * 75 = 7,725 ft^2
Answer:
2x + 12
Step-by-step explanation:
2(10)+2(x+4)
distribute the 2
20 + 2x - 8
add/ subtract like terms
2x + 12
Answer:
a:c = 35:24
a:c = 20:27
a:c = 35:22
a:c = 28:27
Step-by-step explanation:
a:b = 7:3
Using cross products
3a = 7b
Divide by 7
3a/7 = b
Now we want
8b = 5c
Substitute in 3a/7 for b
8 (3a/7) = 5c
24/7a = 5c
Multiply by 7
24/7a *7 = 5*7c
24a = 35c
Divide by c
24 a/c = 35
Divide by 24
a/c = 35/24
a:c = 35:24
a:b = 4:9
Using cross products
9a = 4b
Divide by 4
9a/4 = b
Now we want
3b = 5c
Substitute in 9a/4 for b
3 (9a/4) = 5c
27/4a = 5c
Multiply by 4
27/4a *4 = 5*4c
27a = 20c
Divide by c
27 a/c = 20
Divide by 27
a/c = 20/27
a:c = 20:27
b:c = 5:11
Using cross products
11b = 5c
Divide by 11
b = 5c/11
Now we want
2a = 7b
Substitute in 5c/11 for b
2a = 7(5c/11)
2a = 35c/11
Multiply by 11
2a*11 = 35c
22a = 35c
Divide by c
22 a/c = 35
Divide by 22
a/c = 35/22
a:c = 35:22
b:c = 14:3
Using cross products
3b = 14c
Divide by 3
b = 14c/3
Now we want
9a = 2b
Substitute in 14c/3 for b
9a = 2(14c/3)
9a = 28c/3
Multiply by 3
9a*3 = 28c
27a = 28c
Divide by c
27 a/c = 28
Divide by 27
a/c = 28/27
a:c = 28:27
The horizontal distance from the firefighter at which the maximum height of water occurs is 10.83m
<u>Explanation:</u>
Given:
h(x) = -0.026x² + 0.563x + 3
where,
h(x) is the height of the water
Initial speed, u = 14m/s
angle, θ = 30°
(a)
Horizontal distance = ?
h(x) = ax² + bx + c
the vertex is found at x = -b/2a
where,
x = distance to the maximum height
As compared to the equation given:
a = -0.026
b = 0.563
Thus,
Therefore, horizontal distance from the firefighter at which the maximum height of water occurs is 10.83m
4x + 15
24 - 8x - 9 + 12x
Add or subtract the common variables
4x + 15
