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lord [1]
3 years ago
8

Solve the equation cos2x = -1\2, for 0 < x < 360°.​

Mathematics
1 answer:
natta225 [31]3 years ago
6 0

Answer:

x = 60°, 120°

Step-by-step explanation:

If we let t=2x, our equation now becomes \cos{t}=-1/2, which is true for two values of t: 120° and 240°. Since t = 2x, we can say that 120^{\circ}=2x and 240^{\circ}=2x, and therefore x = 60^{\circ} and x=120^{\circ}

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The slope field for the differential equation dy/dx=(3y)/(xy+5x) will have vertical segments when
Inessa05 [86]

Answer:

E) x=0 or y=-5

Step-by-step explanation:

The slope field will have vertical segments when dy/dx is undefined, that is, dy/dx is a division by 0.

We have that

dy/dx=(3y)/(xy+5x)

So the slope field will have vertical segments when

xy + 5x = 0

x(y + 5) = 0

This is when x = 0 or y = -5.

So the correct answer is:

E) x=0 or y=-5

3 0
3 years ago
What number is 25% of 400 please show work thank you
ANEK [815]

Answer:

100

Step-by-step explanation:

well, you can just use a calculator, or your mind if that's possible, to solve this.

at least, what i think you're asking.

400 × 0.25 = 100.

this one is extra easy because you should know that 25% is a quarter, and 400 can just be divided by 4 to get your answer.

6 0
2 years ago
What is the ratio of the number of sides of a quadrilateral to the number of sides of a pentagon?
IgorC [24]
4:5 because a quadrilateral has 4 sides and a pentagon has 5 sides
3 0
3 years ago
PLZZ HELP!! WILL MARK BRAINLIEST PLZZ!!!
grandymaker [24]

Answer:

see below

Step-by-step explanation:  7  1  16   33

  y  = x²   translated t the point (3, 2)         y = 0 when x = 0

  y =  (x - 3)²    moves the function three units to the right     y = 0 when x = -3

  y  = (x-3)² + 2  moves the function up 2 units      y = 2 when x = -3

  y = (x-3)² + 2

  y = x² - 6x + 9 + 2

  y = x² - 6x +11

graph the equations x²,  (x-3)² + 2,  and x² - 6x + 11   to verify (I did)

7 0
3 years ago
Write an equation of the line passing through point p that is perpendicular to the given line. p(3,1), y=13x−5
Anarel [89]
You know two lines y=ax+b and y=mx+n that are perpendicular, so we have the product a*m=-1

+ This line is perpendicular to y=13x-5, so it has equation: y=-1/13x+b
+ And it passes through the point (3;1), so we have x=3, y=1. So 1=-1/13 *3+b
and b= 1+3/13= 16/13
And we have y=-1/13x+16/13
Have fun
7 0
3 years ago
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