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3 years ago

What are the domain values for the function f(x) = 2x + 3 if the range values are (-1, 1, 2,4}

Mathematics

1 answer:

ArbitrLikvidat [17]3 years ago

7 0

Answer:

Another way to identify the domain and range of functions is by using graphs. Because the domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis. The range is the set of possible output values, which are shown on the y-axis.

So i think it will be -1

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In a toy factory 200 wooden soils cylinders 7 cm long and 35 mm in diameter have to be painted. What is the total surface area i

emmainna [20.7K]

By applying 2×pie×radius (radius+height)
This answer comes 1925000mm^3

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2 years ago

Use the method of reduction of order to find a second independent solution of the given differential equation. t2y'' + 3ty' + y

Charra [1.4K]

I assume you mean $y_1=t^{-1}$ , and not $y_1=t-1$ , since this doesn't satisfy the ODE.

Assume a second solution of the form $y_2=vy_1$ , where $v$ is a function of $t$ . Then

${y_2}'=v'y_1+v{y_1}'$

${y_2}''=v''y_1+2v'{y_1}'+v{y_1}''$

Substituting into the ODE gives

$t^2\left(\dfrac{v''}t-\dfrac{2v'}{t^2}+\dfrac{2v}{t^3}\right)+3t\left(\dfrac{v'}t-\dfrac v{t^2}\right)+\dfrac vt=0$

$\implies tv''+v'=0$

$\implies(tv')'=0$

$\implies tv'=C$

$\implies v'=\dfrac Ct$

$\implies v=C_1\ln|t|+C_2$

$\implies y_2=\dfrac{\ln t}t$

where we omit the second term because it's already accounted for by $y_1$ .

3 0

3 years ago

(8.88×10^4) + (7.48×10^4)

podryga [215]

1.636x10^5 after adding or 163600 depending on the form wanted

4 0

3 years ago

Help solving this math problem

daser333 [38]

Diagram of two triangles

The two triangles are similar because they are both right triangles, meaning that one angle is 90° and the other two are acute (less than 90°).

The diagram on the left is missing its hypotenuse - the variable c. The hypotenuse is opposite of the right angle. The diagram on the right side is missing one of its legs.

Note: The hypotenuse is the longest side of a right triangle.

Word Problen

The legs are 21 blocks and 20 blocks because they are by the right angle. Use the Pythagorean theorem to find the diagonal path's length, which is the hypotenuse.

${a}^{2} + {b}^{2} = {c}^{2}$

Standard form of Pythagorean theorem.

${21}^{2} + {20}^{2} = {c}^{2}$

Equation with the legs substituted and the missing hypotenuse value - c.

$841 = {c}^{2}$

Square the legs and add.

$\sqrt{841} = c$

$29 = c$

Take the square root and simplify. The square root of 841 is 29 and -29, but distance is positive.

Thus the diagonal distance is 29 blocks.

Check by substituting.

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3 years ago

Which line contains the point (1,-3)

Rzqust [24]

There are infinitely many lines that have the point (1,-3).

A line can be expressed as:

y=mx+b, where m=slope and b=y-intercept..

Our only restriction is that it passes through (1,-3) so

-3=1m+b

So as long as the sum of the slope and the y-intercept is equal to -3, that is one of the infinite number of lines that passes through (1, -3)

So we could also say b=-3-m then our infinite lines are:

y=mx-3-m, now any real value of m creates a specific line that passes through the point. ie the first few are

y=x-4, y=2x-5, y=3x-6 or even y=x√2-3-√2

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3 years ago