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Brrunno [24]
2 years ago
8

How here needs help i m a teacher that helps answer this Math Quiz

Mathematics
2 answers:
OLga [1]2 years ago
8 0

Answer:

5+3+10+1000=1, 018?

Step-by-step explanation:

am i right?if im right pls brainliest thank you

sweet [91]2 years ago
5 0

Answer:

The mean is 254.5

Step-by-step explanation:

Add up all the numbers then divide by how many numbers there are.

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I still don't get how to do this: Solve for t then simplify your answer. -6/5t=9
stepladder [879]

Answer:

t= \frac{-15}{2}

Step-by-step explanation:

Multiply both sides by 5/(-6).

\frac{5}{-6} *\frac{-6}{5}=\frac{5}{-6}*9

ik the doesnt rlly make any sense but hope this helps

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3 years ago
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Please help me I don’t understand this
Tomtit [17]

Answer:64

Step-by-step explanation:

67

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2 years ago
If jenny has 1,490÷6 how will you solve it.
puteri [66]
It's 248.3333 (but with the 3s repeating)
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Carly bought a new house for $125,000. The value of the house appreciates approximately 3.5% each year. What will be the value o
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3 years ago
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Triangle $ABC$ has a right angle at $B$. Legs $\overline{AB}$ and $\overline{CB}$ are extended past point $B$ to points $D$ and
Lisa [10]

Answer:

Given :

ABC is a right triangle in which ∠ABC = 90°,

Also, Legs AB and CB are extended past point B to points D and E,

Such that,

\angle EAC = \angle ACD = 90^{\circ}

To prove :

EB\times BD=AB\times BC

Proof :

In triangles AEC and EBA,

∠EAC= ∠ABE ( right angles )

∠CEA = ∠AEB ( common angles )

By AA similarity postulate,

\triangle AEC \sim \triangle EBA,

Similarly,

\triangle AEC \sim \triangle ABC

\implies\triangle EBA\sim \triangle ABC-----(1)

Now, In triangles ADC and CBD,

∠ACD = ∠CBD ( right angles )

∠ADC= ∠BDC ( common angles )

By AA similarity postulate,

\triangle ADC \sim \triangle CBD,

Similarly,

\triangle ADC \sim \triangle ABC

\implies \triangle CBD\sim \triangle ABC-----(2)

From equations (1) and (2),

\triangle EBA\sim \triangle CBD

The corresponding sides of similar triangles are in same proportion,

\frac{EB}{BC}=\frac{AB}{BD}

\implies EB\times BD=AB\times BC

Hence, proved....

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3 years ago
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