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gayaneshka [121]
2 years ago
5

The camp cook made 4 1/2 pots of chicken soup. Each serving of soup is 1/2 of a pot. How many servings of chicken soup did the c

ook make?
Mathematics
2 answers:
Alexus [3.1K]2 years ago
7 0

Answer:

9 servings

Step-by-step explanation:

4.5%.5=9 so the cook made 9 servings.

enot [183]2 years ago
3 0
I got nine as well; I’m just showing another way to solve it.
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Find the value of x + 16​
Tamiku [17]

Answer:

x=16,−16

Step-by-step explanation:

:/

8 0
2 years ago
What is the value of x?
Oduvanchick [21]

Answer:

x = 19

Step-by-step explanation:

Vertical angles are equal

So

7x - 8 = 6x + 11

7x - 6x = 11 + 8

x = 19

7 0
2 years ago
Mathematics <br> Simple events likelihood experimental probability
saw5 [17]

Problem 1

Answer: Closer to 1

Explanation:

There are 20 gumballs total. Half of this is 20/2 = 10 gumballs. If there's more than 10 of one color, then the probability of getting that color is closer to 1, than it is to 0. Here we have 12 pink which is greater than 10, so that's why the answer is closer to 1.

================================================

Problem 2

Answer: Closer to 0

Explanation:

The amount of green (3) is less than 10, so that's why the probability is closer to 0 than it is to 1. We can see that 3/20 = 0.15 is less than 0.50

================================================

Problem 3

Answer: Closer to 0

Explanation:

We have a similar situation compared to problem 2. This time we have 5/20 = 0.25 which is less than 0.50

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Problem 4

Answer: 48% chance; fairly likely

Explanation:

We have 12 green out of 25 total, so the probability of choosing green is 12/25 = 0.48 = 48%. While this probability is not over 50%, I still say it's fairly likely considering the other colors lead to smaller probabilities. For instance, purple has a chance of 6/25 = 0.24 = 24% and orange has a probability of 2/25 = 0.04 = 4%, both of which are smaller than 48%

3 0
2 years ago
The half-life of cesium-137 is 30 years. Suppose we have a
VMariaS [17]
(a) If y(t) is the mass (in mg) remaining after t years, then y(t) = y(0) e^{kt}=100e^{kt}.

y(30) = 100 e^{30k} = \frac{1}{2}(100) \implies e^{30k} = \frac{1}{2} \implies k = -(\ln 2) /30 \implies \\ \\&#10;y(t) = 100e^{-(\ln 2)t/30} = 100 \cdot 2^{-t/30}

(b) y(100) = 100 \cdot 2^{-100/30} \approx \text{9.92 mg}

(c)
100 e^{- (\ln 2)t/30} = 1\ \implies\ -(\ln 2) t / 30 = \ln \frac{1}{100}\ \implies\ \\ \\&#10;t = -30 \frac{\ln 0.01}{\ln 2} \approx \text{199.3 years}
 
3 0
3 years ago
Find the value of (– 3 /8 ) × (+8 /15). A. 11/23 B. – 1 /5 C. 11/15 D. – 1 /3
PtichkaEL [24]

(-3/8)(+8/15)

Answer will be a negative number. Whenever multiplying a - negative number * a + positive = - negative number.

(-3/8)(+8/15)

Cross out -3 and 15 . Divide by 3. -3/3,=-1 15/3

= -1/5

Cross out 8 and 8. Divide by 8.

8/8= 1 , 8/8= 1

-1/5*1/1= -1/5

Answer : -1/5

4 0
2 years ago
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