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yarga [219]
3 years ago
13

Charlie made $168 for working an eighth hour day yesterday. write an equation that shows the relationship between the amount of

money (c) made for any number of hours (h)
Mathematics
1 answer:
MissTica3 years ago
7 0
168/8 = x
x=21

Thus your equation is 21x where x equals amount of hours worked and 21 equals the amount he makes per hour
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How to determine if the function has x-axis sym, y-axis sym, and origin sym<br><br> y^2 -xy =2
n200080 [17]

To check for symmetry on the x axis, replace y with –y

-y^2 –x(-y) =2

<span> Apply the product rule, since the equation is not identical tot eh original equation it is not symmetric about the x axis</span>

<span> Now do the same for y axis by replacing x with –x</span>

<span> Again using product rule the equations are not identical, so it is not symmetric about the y axis</span>

<span> To check the origin,</span>

<span> Replace both x & y with –x  & -y</span>

Again using product rule, the equations are not identical so it is not symmetric about the origin


8 0
3 years ago
Please help! Brainliest:)
Nataliya [291]

Answer:

㏑(\frac{b7}{9})

solution

log10 (\frac{b7}{9 }  = \frac{7log 10 (b)}{9}

steps \frac{log10(b7)}{9}

simplify log 10(b7) : 7log10 (b)

= \frac{7log10(b)}{9}

8 0
2 years ago
Allison lives 380 miles from her grandmother. She plans to drive to her grandmother's house for the weekend. She will drive an a
Alisiya [41]

Answer:

its b

Step-by-step explanation:

5 0
3 years ago
Find the value of x round to the nearest 10th
Solnce55 [7]

Answer:

  x ≈ 12.9

Step-by-step explanation:

In relation to the angle in this right triangle, the sides marked are the adjacent side and the hypotenuse. The relevant trig relation is ...

  Cos = Adjacent/Hypotenuse

  cos(72°) = 4/x

Multiplying by x/cos(72°), we have ...

  x = 4/cos(72°)

  x ≈ 12.9

7 0
2 years ago
The diagram above shows a circle with centre O and radius 25 cm.
Salsk061 [2.6K]

Answer:

Step-by-step explanation:

Notice that KL = LM and PQ = QR since OL and OQ are perpendicular to both KM and PR.

It follows that QR = (1/2) PR = 20 cm. We also know that MR = 21.

Now in order to solve the problem we just need OQ=OL

OQ^2=OR^2-QR^2= 25^2-20^2 =225\\OQ=15

Therefore the perimeter of the pentagon is

OL+LM+MR+RQ+Q)\\= 15+20+21+20+15= 91

8 0
3 years ago
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