Answer:
0.5798 or 57.98%
Step-by-step explanation:
The total number of ways to form the two teams is the combination of choosing 10 people out of 35 (₃₅C₁₀). The number of possibilities that A and B are both on the 10-people team is given by the combination of choosing 8 people (since two are fixed) out of 33 (₃₃C₈).The number of possibilities that A and B are both on the 25-people team is given by the combination of choosing 10 people out of 33 (₃₃C₈).
Therefore, the probability that two particular people A and B will be on the same team is:

The probability is 0.5798 or 57.98%.
<span>3x=4y=7z
so
GCF:
3 * 4 * 7 = 84
3x = 84
x = 28
4y = 84
y = 21
7z = 84
z = 12
</span><span>least possible value for
</span><span>x + y + z = 28 + 21 + 12 = 61
</span>
answer
(d) 61