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Reika [66]
2 years ago
7

Can someone help me with this problem? 3 + (-7 + y)

Mathematics
2 answers:
Tomtit [17]2 years ago
7 0

Answer:

it should be  -4+y

Step-by-step explanation:

vladimir2022 [97]2 years ago
7 0

Answer:

−4+y

Step-by-step explanation:

3+(−7+y)

Subtract 7 from 3 to get −4.

−4+y

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Gordo is a fisherman. Darrin claims that Gordo over-estimates the size of his fish by 25%.
White raven [17]

Answer:

The answer will be 30cm

Because 40 divided by 4 is 10 and times it by 3

8 0
2 years ago
I will give brainliest if you answer this simple question.
Citrus2011 [14]

Answer:

2

Step-by-step explanation:

5-3=2 you subtract to get the answer

7 0
3 years ago
Read 2 more answers
Noah's oven thermometer gives a reading that is 2% greater than the actual temperature if the actual temperature is 350°F what w
blsea [12.9K]

Answer:

<h2>357°F </h2>

Step-by-step explanation:

Step one:

given data

actual reading= 350°F

thermometer reading 2% of the actual reading

Step two:

Required:

The thermometer reading

let us find 2% of 350°F

2/100*350°

=0.02*350

=7°F

Hence the thermometer reading is 7°F greater than  350°F

The thermometer reading is 350+7=357°F

6 0
3 years ago
1. The triangles above are similar. What is the ratio (larger to smaller) of the perimeters? (1 point)
eimsori [14]

Answer:

Ratio = 5/3

The ratio (larger to smaller) of the perimeters is 5/3

Step-by-step explanation:

Attached is an image of the two triangles.

Since both triangles are similar, the ratio of their perimeter is equal to the ratio of each similar sides.

Ratio = P1/P2 = S1/S2

Similar side for triangle 1 S1 = 15ft

Similar side for triangle 2 S2 = 9ft

Substituting the values;

Ratio = 15ft/9ft = 5/3

Ratio = 5/3

The ratio (larger to smaller) of the perimeters is 5/3

7 0
3 years ago
A horse might drink 50L, a sheep might drink 4L and a chicken might drink 200ML. How much water would a farm with 3 horses, 15 s
Ilia_Sergeevich [38]
50L x 3 = 150. 4L x 15 = 60. 0.2L x 12 = 2.4. 150 + 60 + 2.4 = 212.4L.
5 0
3 years ago
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