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igor_vitrenko [27]
2 years ago
9

I need help plz it’s due tonight !!!!!!!

Mathematics
1 answer:
lisabon 2012 [21]2 years ago
8 0

Answer:

hmm it's like ut I do know and my answer

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If two people are randomly​ selected, what is the probability both are hopelessly romantichopelessly romantic​? what is the prob
vova2212 [387]
I'm so sorry i dont know the answer
5 0
3 years ago
Which of the following shows that polynomials are closed under subtraction when polynomial x + 5 is subtracted from 3x2 + 2x − 6
Art [367]
For this case we have the following polynomials:
 P = 3x ^ 2 + 2x - 6

Q = x + 5
 By subtracting both polynomials we have:
 P - Q = (3x ^ 2 + 2x - 6) - (x + 5)

 What we must do is subtract terms of the same degree.
 We have then:
 P - Q = 3x ^ 2 + (2x - x) + (-6 - 5)

P - Q = 3x ^ 2 + x - 11
 Answer:
 
3x ^ 2 + x - 11 will be a polynomial
3 0
4 years ago
Gghjuyhyghggjtfdfhhhfgjfhhf​
topjm [15]

Hello.

Have a beautiful and joyful day ahead.

3 0
3 years ago
Read 2 more answers
If 15% of an item is $18 what is the original price??
stiks02 [169]

Answer:

If you were trying to find 15% of 18, that would be multiplying a decimal, but, you need to mutliply a whole number. $120 should be your answer. People, correct me if I'm wrong (seriously though, not 100% sure if this is correct).

Step-by-step explanation:

18 = 15% x Y

18 = 15/100 x Y

Y = 18 × 100/15

Y = 18 × 100 ÷ 15

Y = 120

6 0
3 years ago
How many liters each of a 35% acid solution and a 80% acid solution must be used to produce 60 liters of a 65% acid solution? (R
serg [7]

Solving a system of equations we will see that we need to use <u>40 liters of the 80% acid solution</u>, and the other <u>20 liters are of the 35% acid solution</u>.

<h3>How many liters of each solution do we need to use?</h3>

First, we need to define the variables:

  • x = liters of the 35% acid used.
  • y = liters of the 80% acid used.

We know that we want to produce 60 liters of 65% acid, then we have the system of equations:

x + y = 60

x*0.35 + y*0.80 = 60*0.65

(in the second equation we wrote the percentages in decimal form).

To solve this we need to isolate one of the variables in one equation and then replace it in other one, isolating x we get:

x = 60 - y

Replacing that in the other equation:

(60 - y)*0.35 + y*0.80 = 60*0.65

y*(0.80 - 0.35) = 60*(0.65 - 0.35)

y*0.45 = 60*0.30

y = 60*0.30/0.45 = 40

So we need to use <u>40 liters of the 80% acid solution</u>, and the other <u>20 liters are of the 35% acid solution</u>.

If you want to learn more about systems of equations:

brainly.com/question/13729904

#SPJ1

7 0
2 years ago
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