Answer:
4z4−6z3−2z2−20z+1
Step-by-step explanation:
4z5−14z4+10z3−16z2+41z−2
z−2
=
4z5−14z4+10z3−16z2+41z−2
z−2
=
(z−2)(4z4−6z3−2z2−20z+1)
z−2
=4z4−6z3−2z2−20z+1
(theres no more like terms so u cant)
If the probability of observing at least one car on a highway during any 20-minute time interval is 609/625, then the probability of observing at least one car during any 5-minute time interval is 609/2500
Given The probability of observing at least one car on a highway during any 20 minute time interval is 609/625.
We have to find the probability of observing at least one car during any 5 minute time interval.
Probability is the likeliness of happening an event among all the events possible. It is calculated as number/ total number. Its value lies between 0 and 1.
Probability during 20 minutes interval=609/625
Probability during 1 minute interval=609/625*20
=609/12500
Probability during 5 minute interval=(609/12500)*5
=609/2500
Hence the probability of observing at least one car during any 5 minute time interval is 609/2500.
Learn more about probability at brainly.com/question/24756209
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Answer:
Horizontal lines are parallel to the x-axis
The answer is the second option
