Answer:
A
Step-by-step explanation:
only Ali's way would work in this situation. since there is a 5 on the right side, you can not use the zero product property. this only works if the right side is 0. so, you must use Ali's method.
Answer:
So this is scientific notation what you do is
2.9x10^5 so you put however many zeros the is powered to 10. See there is a 5 It has to be behind or in front of the decimal you might be saying how do you know if its behind or in front well negative is in front and positive is behind .
<u><em>290,000 </em></u>there was a number already behind the decimal so there you go 5 number behind the decimal.
Same for the second one
<u><em>290,000</em></u><em> </em><u><em>870,000</em></u> is your answers so now you add hem together
<em><u>1,160,000 is your final answer </u></em>
Step-by-step explanation:
Step-by-step explanation:
The area would be 9 times compared to the area of the original square. To test this, you can let the side of the original square be equal 1. By tripling this side, the side becomes three. Utilizing the area of a square formula, A= s^2, the area of the original square would be 1 after substituting 1 for s. Then, you do the same for the area of the tripled square. With the substitution, the area of the tripled square would be 9. This result displays the area of the tripled square being 9 times as large as the area of the original square. This pattern can be used for other measurements of the square such as:
let s = 2, Original Area= 2^2 = 4 Tripled Area= (2(3))^2 = 6^2= 36. 36/4 = 9
let s = 3, Original Area = 3^2 = 9 Tripled Area - (3(3))^2 = 9^2 =81. 81/9 = 9
let s = 4, Original Area = 4^2 = 16 Tripled Area - (4(3))^2 = 12^2 = 144. 144/16 = 9
let s = 5, Original Area = 5^2 = 25 Tripled Area - (5(3))^2 = 15^2 = 225. 225/25 = 9
let s = 6, Original Area = 6^2 = 36 Tripled Area - (6(3))^2 = 18^2 = 324. 324/36 = 9
let s = 7, Original Area = 7^2 = 49 Tripled Area - (7(3))^2 = 21^2 = 2,401. 2,401/49 = 9
You can continue to increase the length of the square and follow this pattern and it will be consistent.
Here;
Y=(3×22)/11. [ By Cross Multiply]
Y=66/11
:Y=6
May be Helpful.
Thank You
