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Tema [17]
2 years ago
10

Leroi and Sylvia both put $100 in a savings account. Leroi decides he will put in an additional $10 each week. Sylvia decides to

put in an additional 10% of the amount in the account each week.
Who has more money after the first additional deposit? Explain.

Who has more money after the second additional deposit? Explain.
Mathematics
2 answers:
kati45 [8]2 years ago
7 0
Leroi’s account

$100
After first deposit = $100+$10=$110
After second deposit= $110 + $10 = $120


Sylvia’s account

$100
10% of $100 is $10
After first deposit = $100+ $10 = $110
10% of $110 = $11
After second deposit = $110 + $11 = $121

Therefore after their first deposit, both will have the same value in their accounts.
But after the second deposit, Sylvia will have 1$ more in her account than Leroi.
Taya2010 [7]2 years ago
7 0

Answer:

ok just follow these steps

Step-by-step explanation: part over whole like this    part                       then            percent over 100% like this                                  percent

                                          -----------over                  ------------------

                                             whole                                 100%

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Norma-Jean [14]

Answer:

A) α = 0.04136

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Step-by-step explanation:

We are given;

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μ = 400 × 0.6 = 240

Standard deviation is given by;

σ = √npq

Where q = 1 - p = 1 - 0.6 = 0.4

σ = √(400 × 0.6 × 0.4)

σ = √96

σ = 9.8

A) our null hypothesis is at p = 0.6

Probability of making a type I error means we reject the null hypothesis when it is true.

This can be expressed in reference to the question as;

α = P(x < 220) + P(x > 260) all at p = 0.6

Now,

P(x < 220) = z = (x¯ - μ)/σ = (220 - 240)/9.8 = -2.04

Also;

P(x > 260) = z = (260 - 240)/9.8 = 2.04

Now, from z-distribution table probability of a z-score of -2.04 is 0.02068.

Also, probability of z-score of 2.04 is (1 - P(z < 2.04) = 1 - 0.97932 = 0.02068

Thus;

α = 0.02068 + 0.02068

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B) Type II error occurs when we fail to reject the null hypothesis even though it's false.

In this case our alternative hypothesis is at p = 48% = 0.48

Thus;

μ = np

μ = 400 × 0.48 = 192

Standard deviation is given by;

σ = √npq

Where q = 1 - p = 1 - 0.48 = 0.52

σ = √(400 × 0.48 × 0.52)

σ = √99.84

σ = 9.992

Type II error would be given by;

β = [((x1¯ - μ)/σ) < z > ((x2¯ - μ)/σ)]

β = [((220 - 192)/9.992) < z > ((260 - 192)/9.992)]

β = (2.8 < z > 6.81)

Rearranging this gives us;

β = P(z < 6.81) - P(z < 2.8)

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β = 1 - 0.99744

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Practice working with reflections.
Alinara [238K]

Answer: The rule of the reflection is rx-axis(x, y) → (x, –y) ⇒ 3rd answer

Step-by-step explanation:

Let us revise the reflection on the axes

If point (x , y) reflected across the x-axis , then its image is (x , -y) , the rule of reflection is rx-axis (x , y) → (x , -y)

If point (x , y) reflected across the y-axis , then its image is (-x , y) , the rule of reflection is ry-axis (x , y) → (-x , y)

In Δ LMN

∵ L = (-4 , 2)

∵ M = (-5 , 4)

∵ N = (-2 , 3)

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∵ L' = (-4 , -2)

∵ M' = (-5 , -4)

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The signs of y-coordinates of the vertices of Δ LMN are changed, that means Δ LMN are reflected across the x-axis

∵ The y-coordinate of L is 2 and the y-coordinate of L' is -2

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∴ Δ LMN is reflected across the x-axis

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anyanavicka [17]
Hi there!

To solve this problem, we need to simplify the values inside the parenthesis first.

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Now, we distribute the 0.5 into the parenthesis:

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Now, we subtract 13.5 from both sides:

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