Answer:
Solution : Option B, or 9π
Step-by-step explanation:
We are given that y = x, x = 3, and y = 0.
Now assume we have a circle that models the given information. The radius will be x, so to determine the area of that circle we have πx². And knowing that x = 3 and y = 0, we have the following integral:

So our set up for solving this problem, would be such:

By solving this integral we receive our solution:
![\int _0^3x^2\pi dx,\\\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx\\=> \pi \cdot \int _0^3x^2dx\\\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1}\\=> \pi \left[\frac{x^{2+1}}{2+1}\right]^3_0\\=> \pi \left[\frac{x^3}{3}\right]^3_0\\\mathrm{Compute\:the\:boundaries}: \left[\frac{x^3}{3}\right]^3_0=9\\\mathrm{Substitute:9\pi }](https://tex.z-dn.net/?f=%5Cint%20_0%5E3x%5E2%5Cpi%20dx%2C%5C%5C%5Cmathrm%7BTake%5C%3Athe%5C%3Aconstant%5C%3Aout%7D%3A%5Cquad%20%5Cint%20a%5Ccdot%20f%5Cleft%28x%5Cright%29dx%3Da%5Ccdot%20%5Cint%20f%5Cleft%28x%5Cright%29dx%5C%5C%3D%3E%20%5Cpi%20%5Ccdot%20%5Cint%20_0%5E3x%5E2dx%5C%5C%5Cmathrm%7BApply%5C%3Athe%5C%3APower%5C%3ARule%7D%3A%5Cquad%20%5Cint%20x%5Eadx%3D%5Cfrac%7Bx%5E%7Ba%2B1%7D%7D%7Ba%2B1%7D%5C%5C%3D%3E%20%5Cpi%20%5Cleft%5B%5Cfrac%7Bx%5E%7B2%2B1%7D%7D%7B2%2B1%7D%5Cright%5D%5E3_0%5C%5C%3D%3E%20%5Cpi%20%5Cleft%5B%5Cfrac%7Bx%5E3%7D%7B3%7D%5Cright%5D%5E3_0%5C%5C%5Cmathrm%7BCompute%5C%3Athe%5C%3Aboundaries%7D%3A%20%5Cleft%5B%5Cfrac%7Bx%5E3%7D%7B3%7D%5Cright%5D%5E3_0%3D9%5C%5C%5Cmathrm%7BSubstitute%3A9%5Cpi%20%7D)
As you can tell our solution is option b, 9π. Hope that helps!
Answer:
x = 64°
Step-by-step explanation:
180° in half a circle or a line.
There is also 180° in a triangle.
So the other 2 angles of the triangle equal x.
34° + 30° = 64°
Answer:
A = 5 / P
Step-by-step explanation:
5 / A = P
A = 5 / P
(10x+5)4 = 30x + 3x + 6x +30
40x + 20 = 39x + 30
X = 10
perimeter of the square= 420
perimeter of the triangle= 420