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Mathematics

1 answer:

Monica [59]2 years ago

5 0

Answer:

Lest then 5/8

Step-by-step explanation:

Lest then 5/8

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Someone please help with trig question ASAP!!!! You dont need to do both! Will mark brainliest if right

Zanzabum

Answer:

8 x = 60.10251159

9 x = 3.66062978

Step-by-step explanation:

Hey There!

So to answer these questions we need to use the Law of sines

Consider the following image

So to find x in number 8 we setup an equation

$\frac{x}{sin90} =\frac{48}{sin53}$

now we solve for x

step 1 multiply each side by sin 90

now we have

$x = \frac{48sin90}{sin53}$

if you plug the equation in a calculator you get that

x=60.10251159

<u>( make sure if it says to round to the nearest.... that you round before entering your answer)</u>

For number 9 the equation would be

$\frac{9}{sin90} =\frac{x}{sin24}$

now we solve for x

step 1 multiply each side by sin 24

now we have

$x=\frac{9sin24}{sin90}$

if you plug this into a calculator you get that

x = 3.66062978

<u>(once again if it says to round to the nearest... make sure you round before you put in your answer.)</u>

3 0

2 years ago

Four circles of unit radius are drawn with centers $(1,0)$, $(-1,0)$, $(0,1)$, and $(0,-1)$. a circle with radius 2 is drawn wit

Reika [66]

Check the picture 1.

The regions contained in an odd number of these 5 circles are

the pink colored region, contained only in the circle with radius 2,

and the yellow regions, each contained in the intersection of 2 small circles and the third large circle.

So what we need to determine is the "area pink + area yellow".

Consider the second picture.

Let A2 be the area of the right isosceles triangle, and A1 be half of the yellow region.

the region A2 + A1 is called a sector, and it is 1/4 of the area of a unit circle.

$A1=A_{sector}-A2= \frac{1}{4} \pi r^2- \frac{1}{2}.1.1= \frac{1}{4} \pi 1^2- \frac{1}{2}= \frac{1}{4}\pi- \frac{1}{2}$

Thus, the overall yellow region is $8A1=8(\frac{1}{4}\pi- \frac{1}{2})=2\pi-4$

The purple area is:

Area of large circle - 4*(Area of 1 small circle) + yellow region.

(because subtracting all 4 small circles means that each of the 4 separate yellow regions have been subtracted twice)

$A_{purple}=\pi.2^2-4(\pi.1^2)+2\pi-4=4\pi-4\pi+2\pi-4=2\pi-4$

Finally, the total area is : $2\pi-4+2\pi-4=4\pi-8$ (units squared)

Answer: $6\pi-8$ square units