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Mice21 [21]
3 years ago
7

1/2b+9/4=7/4 solve the equation

Mathematics
1 answer:
AlladinOne [14]3 years ago
4 0
First subtract 9/4 from each side

1/2b=-2/4

Simplify the 2/4

1/2b=-1/2

Divide each side by 1/2

b = -1
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A ships triangular signal flag has a base of 8 inches and an area of 64 square inches. What is the height of the signal flag
Firlakuza [10]
A = (1/2)bh
64 = (1/2)(8)h
16 = h
The height is 16 inches
7 0
3 years ago
Find the value of z ANSWER IS NOT 12. NO LINKS OR SPAMS! THANK YOU!!!!!!​
alexgriva [62]

Answer:

12√3

Step-by-step explanation:

sin 30 =1/2

sin30=a/24. sin=opposit side/Hypotenuse

a is the opposite side of 30

1/2=a/24

a=12

now take pythagoras theroem

24^2=z^2+12^2

576=z^2+144

z^2=576-144

z^2=432

z=√432

z=√144*3

z=12√3

4 0
3 years ago
The National Center for Education Statistics surveyed a random sample of 4400 college graduates about the lengths of time requir
Paha777 [63]

Answer:

95​% confidence interval for the mean time required to earn a bachelor’s degree by all college students is [5.10 years , 5.20 years].

Step-by-step explanation:

We are given that the National Center for Education Statistics surveyed a random sample of 4400 college graduates about the lengths of time required to earn their bachelor’s degrees. The mean was 5.15 years and the standard deviation was 1.68 years respectively.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

                              P.Q. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean time = 5.15 years

            \sigma = sample standard deviation = 1.68 years

            n = sample of college graduates = 4400

            \mu = population mean time

<em>Here for constructing 95% confidence interval we have used One-sample z test statistics although we are given sample standard deviation because the sample size is very large so at large sample values t distribution also follows normal.</em>

<u>So, 95% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5%

                                               level of significance are -1.96 & 1.96}  

P(-1.96 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 1.96) = 0.95

P( -1.96 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} < 1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

P( \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ]

                                              = [ 5.15-1.96 \times {\frac{1.68}{\sqrt{4400} } } , 5.15+1.96 \times {\frac{1.68}{\sqrt{4400} } } ]

                                             = [5.10 , 5.20]

Therefore, 95​% confidence interval for the mean time required to earn a bachelor’s degree by all college students is [5.10 years , 5.20 years].

8 0
3 years ago
Please help once again!!! I need it ASAP!!! It's due very soon!!!
Agata [3.3K]
Number 13 is 79° !!!!!!
6 0
3 years ago
Read 2 more answers
89,659 to the nearest thousand
zubka84 [21]
90,000 is the answer.
8 0
3 years ago
Read 2 more answers
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