Answer:
1
Step-by-step explanation:
n, n + 2, n + 4, n + 6 - four consecutive odd integers
-72 - the sum
The equation:
n + (n + 2) + (n + 4) + (n + 6) = -72
n + n + 2 + n + 4 + n + 6 = -72
4n + 12 = -72 |subtract 12 from both sides
4n = -84 |divide both sides by 4
n = -21
n + 2 = -21 + 2 = -19
n + 4 = -21 + 4 = -17
n + 6 = -21 + 6 = -15
Answer: -21, -19, -17, -15.
If you would like to know how far is Julian from his starting position, you can calculate this using the following steps:
First, you have to make a right triangle, where the hypotenuse of this triangle will actually be the distance we are looking for. The distances of the other two sides are 444 kilometers, and 777 kilometers - 222 kilometers; to be exact: 444 kilometers and 555 kilometers.
The distance we are interested in ... d:
d^2 = 444^2 + 555^2
d^2 = 197136 + 308025 = 505161
d = sqrt(505161)
d = <span>710.7 kilometers
</span>
The correct result would be <span>710.7 kilometers.</span>
Answer:
2.0833
Step-by-step explanation:
2 3/4 + 3 1/2 =6.25
6.25(1/3)=2.0833
Answer:
1.) 6√13/13
2.) 4√13/13
3.) 3
Step-by-step explanation:
given that cot(x) = 2/3
But cot(x) = 1/tan(x)
Substitutes 1/tan(x) for cot(x)
1/tan(x) = 2/3
Reciprocate both sides
Tan(x) = 3/2 = opposite/adjacent
Use pythagorean theorem to find the hypothenus.
Hypothenus = sqrt ( 3^2 + 2^2 )
Hypothenus = sqrt ( 9 + 4 )
Hypothenus = sqrt (13)
Hypothenus = √13
1.) Sin(x) = opposite/hypothenus = 3/√13
Rationalise
3/√13 × √13/√13
3√13/13
Sin(2x) = 2 × 3√13/13
Sin(2x) = 6√13/13
2.) Cos( x ) = adjacent/hypothenus
Cos (x) = 2/√13
Rationalise
2/√13 × √13 /√13
2√13/13
Cos(2x) = 2 × 2√13/13
Cos(2x) = 4√13/13
3.) Tan (x) = 3/2
tan (2x) = 2 × 3/2
Tan(2x) = 3
