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MA_775_DIABLO [31]
3 years ago
11

Absolute value of +4 and -2

Mathematics
2 answers:
densk [106]3 years ago
7 0

Answer:

Step-by-step explanation:

4 and 2

Greeley [361]3 years ago
3 0

Answer:

4 and 2

Step-by-step explanation:

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Which expression can be used to find 25 percent of 88?
Dominik [7]

Answer: 25/100* 88

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
An education researcher claims that 58​% of college students work​ year-round. In a random sample of 400 college​ students, 232
Hatshy [7]

Answer:

The proportion of college students who work​ year-round is 58%.

Step-by-step explanation:

The claim made by the education researcher is that 58​% of college students work​ year-round.

A random sample of 400 college​ students, 232 say they work​ year-round.

To test the researcher's claim use a one-proportion <em>z</em>-test.

The hypothesis can be defined as follows:

<em>H</em>₀: The proportion of college students who work​ year-round is 58%, i.e. <em>p</em> = 0.58.

<em>Hₐ</em>: The proportion of college students who work​ year-round is 58%, i.e. <em>p</em> ≠ 0.58. C

Compute the sample proportion as follows:

 \hat p=\frac{232}{400}=0.58

Compute the test statistic value as follows:

 z=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}}}=\frac{0.58-0.58}{\sqrt{\frac{0.58(1-0.58)}{400}}}=0

The test statistic value is 0.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected.

Compute the p-value for the two-tailed test as follows:

 p-value=2\times P(z

*Use a z-table for the probability.

The p-value of the test is 1.

The p-value of the test is very large when compared to the significance level.

The null hypothesis will not be rejected.

Thus, it can be concluded that the proportion of college students who work​ year-round is 58%.

6 0
4 years ago
Anthony grew 64 plants with 32 seed packets.How many seed packets does Anthony need to have a total of 90 plants in his backyard
adelina 88 [10]
Let the total seed packets needed Anthony to have 90 plants be x.

then,
64:32 :: 90:x
2:1 :: 90:x
90 = 2x
x = 45 seed packets.

________________________

64 plants = 32 seed packets.
1 plant = \frac{32}{64} = \frac{1}{2} seed packets.

90 plants = \frac{1}{2} \times 90 = 45 seed packets.

Anthony need 45 seed packets to have 90 plants.

!! Hope It Helps !!
8 0
3 years ago
4th term of an arithmetic sequence is 23 and its 11th term is 65, what is its common difference​
Rudik [331]

Answer:

d = 6

Step-by-step explanation:

The nth term of an arithmetic sequence is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₄ = 23 and a₁₁ = 65 , then

a₁ + 3d = 23 → (1)

a₁ + 10d = 65 → (2)

Subtract (1) from (2) term by term to eliminate a₁

10d - 3d = 65 - 23

7d = 42 ( divide both sides by 7 )

d = 6

5 0
3 years ago
Why is 3 + (−5) equal to −2?
DedPeter [7]
It is not equal to -2 because the five is a negative so when adding two different integers are subtracted and with a negative sign.
5 0
3 years ago
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