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Mkey [24]
2 years ago
11

1. Which of the following expressions is equivalent to 3 + 3×12 ÷ 4×3?

Mathematics
1 answer:
noname [10]2 years ago
6 0
To find which one is equivalent to 3+3*12/4*3, we need to first evaluate and then compare to other expressions to find which one is equivalent to the expression. Using PEMDAS, we first do the multiplication and division, and then do addition.
3+3*12/4*3 = 3+36/4*3 = 3+9*3 = 3+27 = 30
Now that we know what the expression equals to, we can evaluate other equations until we find the same answer.
6*12/4*3=72/4*3=18*3=48
3+3*12/12=3+3*1=3+3=6
3+3*3*3= 3+27*3=3+81=84
3/36/4*3=9/36/4= 1/4/4 = 1/4*1/4 = 1/16
None of them are equivalent
Hope this helps
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5 0
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liraira [26]
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3 0
3 years ago
Read 2 more answers
F(x) = 4x^2 - 3x + 2kx + 1 
dybincka [34]
f(x)=4x^2-3x+2kx+1=4x^2+(2k-3)x+1\\\\a=4;\ b=2k-3;\ c=1\\\\function\ has\ two\ zeros\ when\ \Delta=b^2-4ac > 0\\\\\Delta=(2k-3)^2-4\cdot4\cdot1=4k^2-12k+9-16=4k^2-12k-7 > 0\\\\a_k=4;\ b_k=-12;\ c_k=-7\\\\\Delta_k=(-12)^2-4\cdot4\cdot(-7)=144+112=256\\\\k_1=\frac{-b_k-\sqrt{\Delta_k}}{2a_k};\ k_2=\frac{-b_k+\sqrt{\Delta_k}}{2a_k}

\sqrt{\Delta_k}=\sqrt{256}=16\\\\k_1=\frac{12-16}{2\cdot4}=\frac{-4}{8}=-\frac{1}{2};\ k_2=\frac{12+16}{2\cdot4}=\frac{28}{8}=\frac{7}{2}\\\\a_k=4 > 0\ (up\ parabola\ arms-see\ the\ picture)\\\\Answer:k\in(-\infty;-\frac{1}{2})\ \cup\ (\frac{7}{2};\ \infty)

6 0
3 years ago
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