what are the slope and the y-intercept of the linear function that is represented by the equation 8x - 2y equals 5

Mathematics

2 answers:

nata0808 [166]3 years ago

8 0

Answer:C

Step-by-step explanation:

svetoff [14.1K]3 years ago

4 0

Rewrite it in y=mx+b form.
So 8x-2y=5
-2y=-8x+5
y=4x-5/2

So the slope is m or 4.
The y intercept is b or -5/2.

You might be interested in

(x + 1 < -1) ∩ (x + 1 < 1)

stealth61 [152]

Answer: ok that’s confusing

Step-by-step explanation:

3 0

3 years ago

Which of the following would be an acceptable first step in simplifying the expression sinx/1-sinx

Paha777 [63]

$\bf \textit{difference of squares}
\\\\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)
\\\\\\
\textit{also recall that }sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)\\\\
-------------------------------$

$\bf \cfrac{sin(x)}{1-sin(x)}\implies \cfrac{sin(x)}{1-sin(x)}\cdot \cfrac{1+sin(x)}{1+sin(x)}\implies \stackrel{first~step}{\cfrac{sin(x)[1+sin(x)]}{[1-sin(x)][1+sin(x)]}}
\\\\\\
\cfrac{sin(x)[1+sin(x)]}{1^2-sin^2(x)}\implies \cfrac{sin(x)[1+sin(x)]}{cos^2(x)}
\\\\\\
\cfrac{sin(x)+sin^2(x)}{cos^2(x)}\implies \cfrac{sin(x)}{cos^2(x)}+ \cfrac{sin^2(x)}{cos^2(x)}
\\\\\\
\cfrac{sin(x)}{cos(x)}\cdot \cfrac{1}{cos(x)}+\cfrac{sin^2(x)}{cos^2(x)}\implies tan(x)sec(x)+tan^2(x)
\\\\\\
tan(x)[sec(x)+tan(x)]$

8 0

3 years ago

Read 2 more answers

Please help me!!!!!!!

pantera1 [17]

The degree is 3.
This video explains it pretty well: https://virtualnerd.com/pre-algebra/polynomials-nonlinear-functions/polynomials/monomial-polynomial-degrees/polynomial-degree-definition

5 0

2 years ago

What is the angle of x?

Snowcat [4.5K]

Answer:

Step-by-step explanation:

There are 540 degrees in a pentagon so take 540-(everything there)= 67

5 0

2 years ago

119. Beatrice decides to deposit $100 per month at the end of every month in a bank with an annual interest rate of 5.5% compoun

sveta [45]

Answer: