Answer:
50mph
Step-by-step explanation:
Say for example car A increases by 10 miles per hour and car B decreases by 10 miles per hour. If car A2 = car B3 then by eliminating a few numbers and finally get to 50 you get the following equation.
A = 50+10
b = 50-10
A = 60
B = 40
A2 = 120
B3 = 120
120 = 120
Answer
120km
let s = the original speed
Write a distance equation; dist = time * speed
3(s-10) = 2(s+10)
3s - 30 = 2s + 20
3s - 2s = 20 + 30
s = 50 km/hr is the original speed
confirm this, find the distances
3(50-10) = 120 km
2(50+10) = 120 km
Answer: Last Option
Cramer's rule says that given a system of equations of two variables x and y then:
For this problem we know that:
Solving we have:
Finally
Answer: 2
Recall from the laws of Logarithms:
Log a - Log b = Log ( a/b )
That means
Log 200 - Log 2 = Log ( 200/2)
= Log 100 , which could be written as
Log
Recall from laws of Logarithms:
Log = b Log a
Therefore:
Log = 2 Log 10
Also from law of Logarithm
Log 10 = 1
Therefore 2 Log 10 = 2 x 1
= 2
Answer:Type of Number Example
Prime Number P=2,3,5,7,11,13,17,…
Composite Number 4,6,8,9,10,12,...
Whole Numbers W=0,1,2,3,4,…
Integers Z=…,−3,−2,−1,0,1,2,3,…