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kvv77 [185]
3 years ago
5

Find the slope of the line y =-4/3x –2/3 .

Mathematics
2 answers:
White raven [17]3 years ago
7 0
The slope is -4/3 because it's the coefficient of x
joja [24]3 years ago
7 0
-4/3 is the slope of this line.
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If you lose by an average of 4 points a game for 8 games, which expression shows the difference between your score and that of y
sweet-ann [11.9K]

okay so the answer is a. and b. since how you put them they are the same. so the answer is -4 x 8


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Is 3.14512 a rational number
zvonat [6]
No it is not because you can't make it into a fraction.
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Amir has $200 budget to spend on a graduation party for his son he already has purchased $122 worth of drinks and party supplies
Bas_tet [7]

Answer: C, D, and E

Step-by-step explanation:

200-122=78 remaining

A: 7*11.75= 82.25

B: 10*11.75= 117.50

C: 9*6.80=61.20

D: 11*6.80=74.80

E: 70*1.10=77.00

F: 71*1.10=78.10

Only C, D and E are below the dollars remaining in the budget.

5 0
3 years ago
A circle is centered at J(3, 3) and has a radius of 12.
stealth61 [152]

Answer:

(-6,\, -5) is outside the circle of radius of 12 centered at (3,\, 3).

Step-by-step explanation:

Let J and r denote the center and the radius of this circle, respectively. Let F be a point in the plane.

Let d(J,\, F) denote the Euclidean distance between point J and point F.

In other words, if J is at (x_j,\, y_j) while F is at (x_f,\, y_f), then \displaystyle d(J,\, F) = \sqrt{(x_j - x_f)^{2} + (y_j - y_f)^{2}}.

Point F would be inside this circle if d(J,\, F) < r. (In other words, the distance between F\! and the center of this circle is smaller than the radius of this circle.)

Point F would be on this circle if d(J,\, F) = r. (In other words, the distance between F\! and the center of this circle is exactly equal to the radius of this circle.)

Point F would be outside this circle if d(J,\, F) > r. (In other words, the distance between F\! and the center of this circle exceeds the radius of this circle.)

Calculate the actual distance between J and F:

\begin{aligned}d(J,\, F) &= \sqrt{(x_j - x_f)^{2} + (y_j - y_f)^{2}}\\ &= \sqrt{(3 - (-6))^{2} + (3 - (-5))^{2}} \\ &= \sqrt{145}  \end{aligned}.

On the other hand, notice that the radius of this circle, r = 12 = \sqrt{144}, is smaller than d(J,\, F). Therefore, point F would be outside this circle.

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3 years ago
Tori examined the pattern of exponents in the table.
vichka [17]

Answer:

The answer is actually B, C, and E

Step-by-step explanation:

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