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Lunna [17]
3 years ago
5

Can someone help me find the fa tor of (128m^2n^5 - 200m^4n^3)? ​

Mathematics
1 answer:
Leona [35]3 years ago
3 0

Answer:

8m^2n^3, 4n-5m, and 4n+5m

Step-by-step explanation:

128m^2n^5-200m^4n^3 <-- Given

m^2(128n^5-200m^2n^3) <-- Factor out m²

m^2n^3(128n^2-200m^2) <-- Factor out n³

8m^2n^3(16n^2-25m^2) <-- Factor out 8

8m^2n^3(4n-5m)(4n+5m) <-- Difference of Squares

Therefore, the factors are 8m^2n^3, 4n-5m, and 4n+5m

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