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2 years ago

The ratio of apples to oranges are 6 to 15. If Johnny has 36 apples, how many oranges does he have? Create a ratio table

Mathematics

1 answer:

polet [3.4K]2 years ago

4 0

apples to orange is 6 : 16

6 --> 36

1 --> 6

.................................

15 ---> 5*15 =75 oranges

he has 36 apples and 75 oranges

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Suppose KLMN ~ PQRS. Find the value of x.

arlik [135]

Complete question is attached.

Answer:

B) 8

Step-by-step explanation:

In this question, KLMN ~ PQRS. This means they are similar shapes.

From the image, we could denote that:

KL ~ PQ

LM ~ QR

Given that:

KL = 12

PQ = 30

QR = 20

LM = x

To find x, let's use tge expression:

$\frac{KL}{PQ} = \frac{LM}{QR}$

$= \frac{12}{30} = \frac{x}{20}$

Cross multiplying, we have:

12 * 20 = 30x

240 = 30x

To find x, let's divide both sides by 30.

$\frac{240}{30} = \frac{30x}{30}$

8 = x

x = 8

The correct option is option B.

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4 years ago

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ra1l [238]

These tables have infinitely many values, but the simplest ones would be:
a) x|y
3|5
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b) x|y
2|1
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Your graph for c would look like the attached picture

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3 years ago

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Answer:

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If the height is 12 inches and the diameter is 16 inches, what is the volume?

tigry1 [53]

Answer:

V = πr²h

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3 years ago

The following set of coordinates most specifically represents which figure? (−5, 6), (−1, 8), (3, 6), (−1, 4) (6 points) Paralle

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Answer:

Rhombus

Step-by-step explanation:

The given points are A(−5, 6), B(−1, 8), C(3, 6), D(−1, 4).

We use the distance formula to find the length of AB.

$|AB|=\sqrt{(-1--5)^2+(8-6)^2}$

$|AB|=\sqrt{16+4}$

$|AB|=\sqrt{20}$

The length of AD is

$|AD|=\sqrt{(-1--5)^2+(6-4)^2}$

$|AD|=\sqrt{16+4}$

$|AD|=\sqrt{20}$

The length of BC is:

$|BC|=\sqrt{(-1-3)^2+(8-6)^2}$

$|BC|=\sqrt{16+4}$

$|BC|=\sqrt{20}$

The length of CD is

$|CD|=\sqrt{(-1-3)^2+(6-4)^2}$

$|CD|=\sqrt{16+4}$

$|CD|=\sqrt{20}$

Since all sides are congruent the quadrilateral could be a rhombus or a square.

Slope of AB $=\frac{8-6}{-1--5}=\frac{1}{2}$

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Since the slopes of the adjacent sides are not negative reciprocals of each other, the quadrilateral cannot be a square. It is a rhombus

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