What is the first step needed to solve (3/4)x-3=-18 ?

Wo runners are saving money to attend a marathon. The first runner has $112 in savings, received a $45 gift from a friend, and w

SpyIntel [72]

Answer:

I believe the last answer is correct

Step-by-step explanation:

Both runners are gaining money

8 0

2 years ago

8/x = 32 <br> ..................

krok68 [10]

Answer:

Step-by-step explanation:

x= 1/4

6 0

2 years ago

Watch day about 75,000 people visit Paris, France. Use commutative property to write two equivalent expressions that could be us

Studentka2010 [4]

Answer:

$5\times 75,000$ and $75,000\times 5$

Step-by-step explanation:

We have been given that about 75,000 people visit Paris, France. We are asked to write two equivalent expressions that could be used to find the number of people that visits over a 5- day period .

To find the number of people over a 5-day period, we will multiply 75,000 people by 5 as:

$\text{Number of people that visits over a 5-day period}=75,000\times 5$

Commutative property of multiplication states that we can multiply numbers in any order.

Upon switching the order while multiplying, we will get:

$\text{Number of people that visits over a 5-day period}=5\times 75,000$

Therefore, our required equivalent expressions would be $5\times 75,000$ and $75,000\times 5$ .

5 0

2 years ago

Tensile-strength tests were carried out on two different grades of wire rod. Grade 1 has 10 observations yielding a sample mean

LuckyWell [14K]

Answer:

$t = \frac{1085-1034}{\sqrt{\frac{52^2}{10} +\frac{61^2}{15}}} = 2.240$

$df = n_1 +n_2 -2 = 10+15-2= 23$

$p_v = 2*P(t_{23} >2.240) = 0.035$

Since the p value is lower than the significance level we have enough evidence to conclude that the true means are different at 5% of significance

Step-by-step explanation:

Data given

$\bar X_1 = 1085$ sample mean for group 1

$\bar X_2 = 1034$ sample mean for group 2

$n_1 = 10$ sample size for group 1

$n_2 = 15$ sample size for group 2

$s_1 = 52$ sample deviation for group 1

$s_2 = 61$ sample deviation for group 2

Solution

We want to check if the two means are equal so then the system of hypothesis are:

Null hypothesis: $\mu_1= \mu_2$

Alternative hypothesis: $\mu_1 \neq \mu_2$

And the statistic is given by:

$t = \frac{\bar X_1 -\bar X_2}{\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}}$

And replacing we got:

$t = \frac{1085-1034}{\sqrt{\frac{52^2}{10} +\frac{61^2}{15}}} = 2.240$

The degrees of freedom are given by:

$df = n_1 +n_2 -2 = 10+15-2= 23$

And the p value would be:

$p_v = 2*P(t_{23} >2.240) = 0.035$

Since the p value is lower than the significance level we have enough evidence to conclude that the true means are different at 5% of significance

8 0

3 years ago

☰ Question (part 1 of 2) This is a two-part question, make sure you answer both parts: Flo Tilla is pedal boating on Lake Azui.

Naddik [55]

For this, we use the given info plus a bit of multiplying and subtraction

part 1)

we know that she's 25 y/m
so 5 minutes simply means 25 × 5
$25 \times 5 = 125 \: yards$

now we simply subtract this from 1000 (the original distance)
$1000 - 125 = 875 \: yards$

part 2)

the total time taken is even easier to find
all we have to do is divide 1000 by 25
$1000 \div 25 = 40 \: minutes$

6 0

2 years ago