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lapo4ka [179]
3 years ago
5

Given that 35.8 x 4.23= 151.434write down a division sum with an answer of 423.​

Mathematics
1 answer:
Nina [5.8K]3 years ago
7 0

Answer:

  151434/358 = 423

Step-by-step explanation:

Every product with non-zero factors can be written as an equivalent division relation.

  a·b = c   ⇒   a = c/b

Here, we have 35.8 × 4.23 = 151.434. This can be written as the equivalent ...

  4.23 = 151.434/35.8

We can multiply this by 100 to get a division relation with a quotient of 423:

  423 = 15143.4/35.8

If we want, we can move the decimal points another place to the right to get ...

  151434/358 = 423

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a coin is tossed and a die is rolled. Find the probability of tossing a tail and then rolling a number greater than 2
rodikova [14]

Answer:

1/3; 33% chance

Step-by-step explanation:

1/2 (prob. of tossing tails) * 2/3 (prob of rolling < 2) = 1/3

5 0
3 years ago
Can someone please help me with #1 through #14 of the geometry angle pairs #6 assignment?​
leonid [27]

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5) linear pair

6) linear pair

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3 0
1 year ago
An advertisement for a popular weight-loss clinic suggests that participants in its new diet program lose, on average, more than
Sedbober [7]

Testing the hypothesis, it is found that:

a)

The null hypothesis is: H_0: \mu \leq 10

The alternative hypothesis is: H_1: \mu > 10

b)

The critical value is: t_c = 1.74

The decision rule is:

  • If t < 1.74, we <u>do not reject</u> the null hypothesis.
  • If t > 1.74, we <u>reject</u> the null hypothesis.

c)

Since t = 1.41 < 1.74, we <u>do not reject the null hypothesis</u>, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

Item a:

At the null hypothesis, it is tested if the mean loss is of <u>at most 10 pounds</u>, that is:

H_0: \mu \leq 10

At the alternative hypothesis, it is tested if the mean loss is of <u>more than 10 pounds</u>, that is:

H_1: \mu > 10

Item b:

We are having a right-tailed test, as we are testing if the mean is more than a value, with a <u>significance level of 0.05</u> and 18 - 1 = <u>17 df.</u>

Hence, using a calculator for the t-distribution, the critical value is: t_c = 1.74.

Hence, the decision rule is:

  • If t < 1.74, we <u>do not reject</u> the null hypothesis.
  • If t > 1.74, we <u>reject</u> the null hypothesis.

Item c:

We have the <u>standard deviation for the sample</u>, hence the t-distribution is used. The test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

The parameters are:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • s is the standard deviation of the sample.
  • n is the sample size.

For this problem, we have that:

\overline{x} = 10.8, \mu = 10, s = 2.4, n = 18

Thus, the value of the test statistic is:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{10.8 - 10}{\frac{2.4}{\sqrt{18}}}

t = 1.41

Since t = 1.41 < 1.74, we <u>do not reject the null hypothesis</u>, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

A similar problem is given at brainly.com/question/25147864

3 0
3 years ago
​Solve the systems of equations: ​ ​ ​​
Sidana [21]
(x,y)=(2,3)
This is Answer
6 0
3 years ago
Y = x2 + 4<br> y = x + 6
Nataliya [291]

Answer:

X=2

Y=8

Step-by-step explanation:

Since both equations are equal to y we can equal both equations

2x+4=x+6

x=2

y=2(2)+4

y=8

4 0
3 years ago
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