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3 years ago

Given that 35.8 x 4.23= 151.434write down a division sum with an answer of 423.

Mathematics

1 answer:

Nina [5.8K]3 years ago

7 0

Answer:

151434/358 = 423

Step-by-step explanation:

Every product with non-zero factors can be written as an equivalent division relation.

a·b = c ⇒ a = c/b

Here, we have 35.8 × 4.23 = 151.434. This can be written as the equivalent ...

4.23 = 151.434/35.8

We can multiply this by 100 to get a division relation with a quotient of 423:

423 = 15143.4/35.8

If we want, we can move the decimal points another place to the right to get ...

151434/358 = 423

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3 years ago

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1 year ago

An advertisement for a popular weight-loss clinic suggests that participants in its new diet program lose, on average, more than

Sedbober [7]

Testing the hypothesis, it is found that:

The null hypothesis is: $H_0: \mu \leq 10$

The alternative hypothesis is: $H_1: \mu > 10$

The critical value is: $t_c = 1.74$

The decision rule is:

If t < 1.74, we do not reject the null hypothesis.
If t > 1.74, we reject the null hypothesis.

Since t = 1.41 < 1.74, we do not reject the null hypothesis, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

Item a:

At the null hypothesis, it is tested if the mean loss is of at most 10 pounds, that is:

$H_0: \mu \leq 10$

At the alternative hypothesis, it is tested if the mean loss is of more than 10 pounds, that is:

$H_1: \mu > 10$

Item b:

We are having a right-tailed test, as we are testing if the mean is more than a value, with a significance level of 0.05 and 18 - 1 = 17 df.

Hence, using a calculator for the t-distribution, the critical value is: $t_c = 1.74$ .

Hence, the decision rule is:

If t < 1.74, we do not reject the null hypothesis.
If t > 1.74, we reject the null hypothesis.

Item c:

We have the standard deviation for the sample, hence the t-distribution is used. The test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.
$\mu$ is the value tested at the null hypothesis.
s is the standard deviation of the sample.
n is the sample size.

For this problem, we have that:

$\overline{x} = 10.8, \mu = 10, s = 2.4, n = 18$

Thus, the value of the test statistic is:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{10.8 - 10}{\frac{2.4}{\sqrt{18}}}$

$t = 1.41$

Since t = 1.41 < 1.74, we do not reject the null hypothesis, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

A similar problem is given at brainly.com/question/25147864

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3 years ago

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3 years ago

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Nataliya [291]

Answer:

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3 years ago

Given that 35.8 x 4.23= 151.434write down a division sum with an answer of 423.​

Given that 35.8 x 4.23= 151.434write down a division sum with an answer of 423.