Question

The function h(x)=12/x-1 is one to one. Algebraically find it’s inverse, h^-1(x).

Answer 1

Answer:

Step-by-step explanation:

hello,

I assume that you mean

$h(x)=\dfrac{12}{x-1}$

so first of all let's take x real different from 1 , as this is not allowed to divide by 0

$(hoh^{-1})(x)=x=h(h^{-1}(x))=\dfrac{12}{h^{-1}(x)-1} \ \ \ so\\h^{-1}(x)-1=\dfrac{12}{x} \\\\h^{-1}(x)=1+\dfrac{12}{x}$

and this is defined for x real different from 0

hope this helps