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2 years ago

NO LINKS AND NO WEBSITES I really need help with this, and also if it's Substitution or linear combination.

1 answer:

3 0

Step: Solve x = −2 for x:

x = −2

Step: Substitute −2 for x in 3x + y = 8:

3x+y=8

(3)(−2)+y=8

y−6=8(Simplify both sides of the equation)

y−6=8 (Add 6 to both sides)
+6 +6

y = 14

Answer:
x = −2
and
y = 14

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55 times 4 and time 3 equals what?

mina [271]

Answer:

55 times 4 =220

220 times 3 =660

7 0

3 years ago

Kesha feeds her dog, Tiny, 8 ounces of dog food each day. How much dog food, in pounds, does she feed Tiny in 20 days?

weeeeeb [17]

8 ounces* 20 days= 160 ounces
160 ounces divided by 16 ounces in a pound= 10 pounds
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6 0

3 years ago

Read 2 more answers

Match the measureable quantity given by its formula with the appropriate unit(s).

kompoz [17]

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Step-by-step explanation:

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3 years ago

Scientists estimate the rate of a kangaroo pouncing at full speed to be 66 feet per second. Write a function rule to describe th

aleksandrvk [35]

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4 0

3 years ago

Zoey made 6 1/2 cups of trail mix for a camping trip. She wants to divide the trail mix into 3/4 cup of servings. Twelve people

AlekseyPX

Answer:

Step-by-step explanation:

Given that:

Total number of cups of trail mix available for camping trip = $6\frac{1}{2}$

Amount of one serving contains = $\frac{3}{4}$ cups

Number of people at the trip = 12

To find:

Whether each person will be able to get the servings?

Solution:

Here, we can find the total number of servings by dividing the total number of cups of trail mix with the amount of one serving.

First of all, let us convert the mixed fraction into fractional number.

$6\dfrac{1}{2} = \dfrac{6\times 2+1}{2} = \dfrac{13}{2}$

Therefore, total number of servings available as per the given quantities:

$\dfrac{\frac{13}2}{\frac{3}4}\\\Rightarrow \dfrac{13\times 4}{2\times 3} \\\Rightarrow \dfrac{26}{3}\\\Rightarrow \approx 8$

So, With this type of servings Zoey will be able to serve only 8 people.

Therefore, there is not enough servings.

7 0

3 years ago

NO LINKS AND NO WEBSITES I really need help with this, and also if it's Substitution or linear combination.​

NO LINKS AND NO WEBSITES I really need help with this, and also if it's Substitution or linear combination.