A rectangle has a length of 11 feet and a perimeter of 38 feet. what is the width, in feet, of the rectangle?
1 answer:
We KNOW the perimeter is 38 & we KNOW the length on ONE side is 11, therefore 11 + 11 = 22 AND 38 - 22 = 16, THUS 16/2 = 8 feet THE ANSWER IS 8 feet
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Answer:
ln (m^2n^9)
Step-by-step explanation:
Rule: ln a + ln b = ln ab
Rule: ln a^n = n * ln a
2 ln m + 9 ln n =
= ln m^2 + ln n^9
= ln (m^2n^9)
= 
Respuesta:
A.) BA = 12 m
Explicación paso a paso:
Usando triángulos similares:
BA / AC = DE / EC
BA = x; AC = 20; DE = 3; EC = 5
POR ESO ; TENEMOS :
x / 20 = 3/5
Multiplicar en cruz:
5 * x = 20 * 3
5 veces = 60
5x / 5 = 60/5
x = 12
Answer:
Frieda's work is correct.
Step-by-step explanation:
z+22= 64 can also be z= 64-22
64-22= 42
Meaning, z= 42
42+22-22= 64-22
42= 42
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Answer:
6x-18
Step-by-step explanation:
(2x-6)+4x-12
6x-18