Answer:
The Journal entry with their narrations shown below:-
Explanation:
The Journal Entry is shown below:-
1. Petty cash Dr, $271
To Cash $271
(Being establishment of petty cash fund is recorded)
2. Freight-in Expenses(delivery charges) Dr, $76
Supplies expenses Dr, $41
Postage expenses Dr, $49
Loan to employees (Accounts receivable) Dr, $33
Miscellaneous expenses Dr, $52
Cash short and over Dr, $8
To Cash $259
($271 - $12)
(Being disbursement of cash is recorded)
3. Petty cash Dr, $116
To cash $116
(Being increase in petty cash is recorded)
Answer:
<em><u>Functional </u></em>
Explanation:
<em>Function</em><em>.</em><em> </em><em>a </em><em>relationship</em><em> </em><em>in </em><em>which </em><em>f</em><em>or </em><em>every </em><em>input</em><em> </em><em>there </em><em>exactly</em><em> </em><em>one </em><em>output</em><em>.</em>
Answer:
He would receive $15 under incentive plan.
Explanation:
The given values are:
Average observed time
= 280 seconds per unit
Performance rating
= 105%
i.e.,
= 1.05
Allowance factor
= 13%
i.e.,
= 0.13
So,
⇒ ![Standard \ time = \frac{(Average \ observed \ time\times Performance \ rating)}{1-Allowance \ factor}](https://tex.z-dn.net/?f=Standard%20%5C%20time%20%3D%20%5Cfrac%7B%28Average%20%5C%20observed%20%5C%20time%5Ctimes%20Performance%20%5C%20rating%29%7D%7B1-Allowance%20%5C%20factor%7D)
On putting the estimated values, we get
![=\frac{(280\times 1.05)}{(1-0.13)}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%28280%5Ctimes%201.05%29%7D%7B%281-0.13%29%7D)
![=\frac{294}{0.87}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B294%7D%7B0.87%7D)
![= 337.93 \ seconds](https://tex.z-dn.net/?f=%3D%20337.93%20%5C%20seconds)
The available time will be:
= ![(8 \ hours\times 60 \ min/hr\times 60 \ sec/min)](https://tex.z-dn.net/?f=%288%20%5C%20hours%5Ctimes%2060%20%5C%20min%2Fhr%5Ctimes%2060%20%5C%20sec%2Fmin%29)
= ![28800 \ seconds](https://tex.z-dn.net/?f=28800%20%20%5C%20seconds)
Now,
The Standard production per day will be:
= ![\frac{Available \ time}{Standard \ time}](https://tex.z-dn.net/?f=%5Cfrac%7BAvailable%20%5C%20time%7D%7BStandard%20%5C%20time%7D)
= ![\frac{28800}{337.93}](https://tex.z-dn.net/?f=%5Cfrac%7B28800%7D%7B337.93%7D)
= ![85.22 \ units](https://tex.z-dn.net/?f=85.22%20%5C%20units)
Since he generates 100 units, he consumes about 15(00-85,22) units per day well above normal production.
So that he's going to get:
= ![15\times 1](https://tex.z-dn.net/?f=15%5Ctimes%201)
=
($)
Answer: A. equal to marginal cost where it intersects the demand curve
Explanation:
In a pure competition, the market is efficient because it balances demand and supply and gives an equilibrium price that takes both of them into account.
In this market, the price is equal to the marginal revenue of a firm and the profit maximizing level of production is where the marginal revenue intersects the marginal cost.
The efficient level is therefore where price equals marginal cost. The same goes for a natural monopoly. If economic efficiency is to be achieved, the natural monopoly's price must equal the marginal cost at the equilibrium price.
The answer is all but D.
the company cannot produce a combination of x,y when the plot is outside the line