Question

Records show that Oliver is typically 10–30 minutes late for his shift at work. The distribution for the minutes he is late forms a consistent pattern, which can be graphed as the given uniform density curve.
A uniform density curve is at y = StartFraction 1 Over 20 EndFraction.

Company policy requires employees to be less than 12 minutes late for work. What percentage of the time will Oliver meet company policy?

6.7%
10%
60%
90%

Answer 1

Based on the information given, the percentage of time that'll be required to meet the policy will be 10%.

From the complete information, the probability distribution will be:

= 1/(b - a) = 1/(30 - 10) = 1/20

Since the company policy requires employees to be less than 12 minutes late for work, the percentage of the time that Oliver will meet company policy will be:

= (12 - 10) × 1/20

= 2 × 1/20

= 1/10

= 10%

In conclusion, the correct option is 10%.

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