Answer:
Part A: x⁴ + x³ + x²
Part B: (4·x + 2) + (-5·x + 6) = -x + 8
Step-by-step explanation:
Part A:
We note that standard form means that the terms of the polynomial are arranged in order starting from the the largest exponential of the polynomial to the smallest exponent
Therefore, we have
x⁴ + x³ + x² is a fourth-degree polynomial with three terms in standard form
It is known that the above polynomial is in standard form based on its ordered arrangement from the largest exponential to the smallest exponential
Part B:
Polynomial are closed under addition, that is when two polynomials are added only the coefficients change as the exponents and variables remain unchanged as follows;
(4·x + 2) + (-5·x + 6)
= 4·x + 2 - 5·x + 6
= 4·x - 5·x + 2 + 6
= -x + 8 which is a polynomial with the same variable and exponent.
Answer:
C. Point A lies on ray BC
Step-by-step explanation:
Points A and C can be connected by a segment which would be a measure of the distance between the points. Locating point B between AC, makes the three points lying on segment AC.
A ray extends from a point to infinity, a line extend to infinity on both sides, while a segment is known to have two endpoints. Therefore, points AC are the end points of the segment AC, and point B between this segment confirms that point B lies on the segment AC. Therefore, Point A lies on ray BC is not correct.
The vector function is, r(t) = 
Given two surfaces for which the vector function corresponding to the intersection of the two need to be found.
First surface is the paraboloid, 
Second equation is of the parabolic cylinder, 
Now to find the intersection of these surfaces, we change these equations into its parametrical representations.
Let x = t
Then, from the equation of parabolic cylinder, 
.
Now substituting x and y into the equation of the paraboloid, we get,
Now the vector function, r(t) = <x, y, z>
So r(t) =
Learn more about vector functions at brainly.com/question/28479805
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Apply division by 10 when one tenth of a number is required and apply multiplication by 10 when 10 times of a number is required.
<u>Solution:</u>
Need to determine what operation is required to get one-tenth of a number and 10 times of a number
To get one tenth of a number, divide the number by 10.
For example to get one – tenth of 100, divide it by 10, we get 10 as a result.
To get ten times of a number, multiply the number by 10
For example 10 times of 10 = 10 x 10 = 100
Hence apply division by 10 when one tenth of a number is required and apply multiplication by 10 when 10 times of a number is required.
