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juin [17]
3 years ago
14

Need help!!!!!!!!!!!!

Mathematics
1 answer:
Xelga [282]3 years ago
8 0

Step-by-step explanation:

the perimeter of a rectangle is

2×length + 2×width =

2×(x + 10y) + 2×(7x² - x + 9y) =

2x + 20y + 14x² - 2x + 18y =

14x² + 38y

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1 2 3 4 ur mom is gone
irga5000 [103]

Answer:

:D Gud ta hear- but Grandpa John wants a blow.job

Step-by-step explanation:

4 0
3 years ago
Use the upper and lower sums to approximate the area of the region using the given number of subintervals (of equal width)
Mashutka [201]
From the figure shown, the interval is divided into 5 equal parts making each subinterval to be 0.2.

Part A:

y= \sqrt{1-x^2}

The approximate the area of the region shown in the figure using the lower sums is given by:

 Area= [y(0.2)\times0.2]+[y(0.4)\times0.2]+[y(0.6)\times0.2]+[y(0.8)\times0.2] \\ +[y(1)\times0.2] \\  \\ =[\sqrt{1-(0.2)^2}\times0.2]+[\sqrt{1-(0.4)^2}\times0.2]+[\sqrt{1-(0.6)^2}\times0.2] \\ +[\sqrt{1-(0.8)^2}\times0.2]+[\sqrt{1-(1)^2}\times0.2] \\  \\ =(0.9798\times0.2)+(0.9165\times0.2)+(0.8\times0.2)+(0.6\times0.2)+(0\times0.2) \\  \\ =0.196+0.183+0.16+0.12=0.659



Part B:

The approximate the area of the region shown in the figure using the lower sums is given by:

 Area= [y(0)\times0.2]+[y(0.2)\times0.2]+[y(0.4)\times0.2]+[y(0.6)\times0.2] \\ +[y(0.8)\times0.2] \\ \\ =[\sqrt{1-(0)^2}\times0.2]+[\sqrt{1-(0.2)^2}\times0.2]+[\sqrt{1-(0.4)^2}\times0.2] \\ +[\sqrt{1-(0.6)^2}\times0.2] +[\sqrt{1-(0.8)^2}\times0.2] \\ \\ =(1\times0.2)+(0.9798\times0.2)+(0.9165\times0.2)+(0.8\times0.2)+(0.6\times0.2) \\ \\ =0.2+0.196+0.183+0.16+0.12=0.859



Part C:

The approximate area of the given region is given by

Area= \frac{0.659+0.859}{2} = \frac{1.518}{2} =0.759
7 0
3 years ago
3. Solve each equation, and check your solution.
Alisiya [41]

1) 2m - 16 = 2m + 4

2m - 2m = 4 + 16

0 = 20 (no solution)

2) -4(r + 2) = 4(2 - 2r)

-(r + 2) = 2 - 2r

-r - 2 = 2 - 2r

-r + 2r = 2 + 2

r = 4

3) 12(5 + 2y) = 4y - (6 - 9y)

60 + 24y = 4y - 6 + 9y

60 + 24y = 13y - 6

24y - 13y = -6 - 60

11y = -66

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7 0
3 years ago
If an average car is about 16 feet long, about how many car lengths should you have between you and that car in front of you if
Elden [556K]

Answer: 9 cars.

Step-by-step explanation:

given data:

average length of a car = 16feet

speed of the driver = 100miles/hr

Solution:

First we would need to convert the Speed of the car from miles/hr to Feet/secs.

To do this we know that 1mile/hr = 1.467 feet/secs

= 100m/hr * 1.467

= 146.7Feet/secs.

So now the number of cars between him would be

= 146.7Feet/secs / 16

= 9.17

approximately there should be 9 cars between you.

3 0
4 years ago
How do i graph the parabola y=2x^2-5x-3
mixer [17]
Substitute the known values of p p and k k into the formula and simplify. Use the properties of the parabola<span> to analyze and </span>graph the parabola<span>. Select a few x x values, and plug them into the equation to find the corresponding </span>y y<span> values. The x x values should be selected around the vertex.</span>
7 0
3 years ago
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