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pochemuha
3 years ago
12

Hey I’ve got the answer for the first question but I’m stuck on this one 5^-3 X 2^-1

Mathematics
1 answer:
Phantasy [73]3 years ago
8 0

Answer:

  • See below

Step-by-step explanation:

a)

  • 6ˣ = 1/216
  • 6ˣ = 1/6³
  • 6ˣ = 6⁻³
  • x = -3

b)

  • 5⁻³ × 2⁻¹ =
  • 1/5³ × 1/2 =
  • 1/(125×2) =
  • 1/250 or 0.004
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Sample equation with decimals
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Answer:

3y + 5.3 = 3.6

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4 years ago
In triangle abc, ab=90 in, bc=80 in, and angle b measures 50°. what is the approximate perimeter of the triangle?
Arlecino [84]
You need to use the Law of Cosines:
AC² = AB² + BC² - 2·AB·BC·cos(b)
       
Therefore, you get:

AC = √(90² + 80² - 2·90·80·cos(50)
      =√5243.86
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Now you can sum up all the sides in order to find the perimeter:

AB + BC + AC = 90 + 80 + 72.4 = 242.4 in

The correct answer is A) 242.4 in

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4 years ago
If -5x*7=1 , then x=
7nadin3 [17]

Answer:

-1/35 = -.0286

Step-by-step explanation:

-5x * 7 = 1

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3 years ago
Solve the system of equations algebraically.
nordsb [41]

Answer: D

Step-by-step explanation:

4x-3y=8\\5x-4y=5

Let's take one of the equations and solve for a variable to use the substitution method.

5x-4y=5\\5x=5+4y\\x=\frac{5+4y}{5}

Now replace this in the first equation.

4x-3y=8\\4(\frac{5+4y}{5})-3y=8\\\frac{20+16y}{5}-3y=8

Separate the terms.

\frac{20}{5}+\frac{16y}{5}-3y=8

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Subtract 4 from both sides to isolate y.

4-4+\frac{16y}{5}-3y=8-4

\frac{16}{5}y-3y=4

Solve the difference.

\frac{16-(3)(5)}{5}y=4\\

\frac{16-15}{5} y=4

\frac{1}{5}y=4

Multiply by the reciprocal or the inverted fraction that is next to y to isolate it.

(\frac{5}{1} )(\frac{1}{5})y=4(\frac{5}{1})

y=20

Now, in order to find x, replace y in any of the two equations.

5x-4y=5\\5x-4(20)=5\\5x-80=5\\5x=5+80\\5x=85\\x=\frac{85}{5}\\x=17

7 0
3 years ago
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