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pochemuha
2 years ago
12

Hey I’ve got the answer for the first question but I’m stuck on this one 5^-3 X 2^-1

Mathematics
1 answer:
Phantasy [73]2 years ago
8 0

Answer:

  • See below

Step-by-step explanation:

a)

  • 6ˣ = 1/216
  • 6ˣ = 1/6³
  • 6ˣ = 6⁻³
  • x = -3

b)

  • 5⁻³ × 2⁻¹ =
  • 1/5³ × 1/2 =
  • 1/(125×2) =
  • 1/250 or 0.004
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3 years ago
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A paint store sells exterior paint for $35.75 a gallon and paint rollers for $6.00 each. Write an equation in standard form for
VLD [36.1K]
The total price for the gallons of paint will be 35.75p

The total price for the rollers will be 6r

So the equation if the customer have 190 will be
price for gallons of paint + price for rollers = 190
35.75p + 6r = 190
<em>(This is the equation)</em>
3 0
3 years ago
Suppose 850 tickets were sold for a game for a total of $1100. If adult tickets cost $1.50 and children tickets cost $1.00, how
Nesterboy [21]
500 adult tickets and 350 children tickets.

Check :
500A($1.5)=$750
350C($1)=$350

$750 + $350 = $1100         AND         500 + 350 = 850 tickets
8 0
3 years ago
Solve the system of linear equations.
sweet-ann [11.9K]

Answer:

  • dependent system
  • x = 2 -a
  • y = 1 +a
  • z = a

Step-by-step explanation:

Let's solve this by eliminating z, then we'll go from there.

Add 6 times the second equation to the first.

  (3x -3y +6z) +6(x +2y -z) = (3) +6(4)

  9x +9y = 27 . . . simplify

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Add 13 times the second equation to the third.

  (5x -8y +13z) +13(x +2y -z) = (2) +13(4)

  18x +18y = 54

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Equations [eq4] and [eq5] are identical. This tells us the system is dependent, and has an infinite number of solutions. We can find them in terms of z:

  y = 3 -x . . . . solve eq5 for y

  x +2(3 -x) -z = 4 . . . . substitute into the second equation

  -x +6 -z = 4

  x = 2 - z . . . . . . add x-4

  y = 3 -(2 -z)

  y = z +1

So far, we have written the solutions in terms of z. If we use the parameter "a", we can write the solutions as ...

  x = 2 -a

  y = 1 +a

  z = a

_____

<em>Check</em>

First equation:

  3(2-a) -3(a+1) +6a = 3

  6 -3a -3a -3 +6a = 3 . . . true

Second equation:

  (2-a) +2(a+1) -a = 4

  2 -a +2a +2 -a = 4 . . . true

Third equation:

  5(2-a) -8(a+1) +13a = 2

  10 -5a -8a -8 +13a = 2 . . . true

Our solution checks algebraically.

6 0
3 years ago
Questions 1-6 of 6 | Page 1 of 1
LenKa [72]

Answer:

Blank 1 = 53 + 90 = 143

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Blank 3 = 0 - 86 = 86

7 0
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