I don't know what the "six-step method" is supposed to be, so I'll just demonstrate the typical method for this problem.
Let <em>x</em> be the amount (in gal) of the 50% antifreeze solution that is required. The new solution will then have a total volume of (<em>x</em> + 60) gal.
Each gal of the 50% solution used contributes 0.5 gal of antifreeze. Similarly, each gal of the 30% solution contributes 0.3 gal of antifreeze. So the new solution will contain (0.5 <em>x</em> + 0.3 * 60) gal = (0.5 <em>x</em> + 18) gal of antifreeze.
We want the concentration of antifreeze to be 40% in the new solution, so we need to have
(0.5 <em>x</em> + 18) / (<em>x</em> + 60) = 0.4
Solve for <em>x</em> :
0.5 <em>x</em> + 18 = 0.4 (<em>x</em> + 60)
0.5 <em>x</em> + 18 = 0.4 <em>x</em> + 24
0.5 <em>x</em> - 0.4 <em>x</em> = 24 - 18
0.1 <em>x</em> = 6
<em>x</em> = 6/0.1 = 60 gal
The point slope form of a straight line is y-y1 = m(x-x1)
y -(-3) = -7(x-5)
y + 3 = -7(x-5)
y = -7x + 35 - 3
y = -7x + 32
1 yard^2 = 0.8361m^2.?
<span>The solution to the problem is as follows:
So he spent (.625 x 400) = $250.00 per m^2. </span>
He paid out (500 x 250) = $125,000 on the deal.
He received (500 / 0.8361) = 598.014592 yard^2 of fabric.
That would have cost (598.014592 x 120) = $71,761.75 locally.
He lost (125,000 - 71,761.75) = $53,238.25 on the deal.
<span>You can rework with the incorrect conversion factor.
I hope my answer has come to your help. God bless and have a nice day ahead!
</span>
