Answer:
12
Step-by-step explanation:
7+5
Answer:
(1, 3)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality
<u>Algebra I</u>
- Coordinates (x, y)
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y = 3
y = -3x + 6
<u>Step 2: Solve for </u><em><u>x</u></em>
- Substitute in <em>y</em>: 3 = -3x + 6
- [Subtraction Property of Equality] Subtract 6 on both sides: -3 = -3x
- [Division Property of Equality] Divide -3 on both sides: 1 = x
- Rewrite/Rearrange: x = 1
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define original equation: y = -3(1) + 6
- Multiply: y = -3 + 6
- Add: y = 3
Answer:
if you meant to put
, then the answer is 7
Step-by-step explanation:
h=-2
+32
solve for t
0=-2
+32
subtract 32 from both sides
-32=-2
divide both sides by -2
16=
find suare root of 16
4= t-3
add 3 to both sides
7 = t
Answer:
0.000000014
Step-by-step explanation:
1.4 ×
=
= 0.000000014
Answer:
The number of red circles to be added would be equal to 8 times the original amount of red circles
Step-by-step explanation:
Let
x ----> the number of red circles
y ----> the number of blue circles
Originally

----> equation A
How many more circles would need to be added to make the ratio of red to blue 3:1
Let
n ----> the number of additional red circles
----> equation B
substitute equation A in equation B

solve for n

therefore
The number of red circles to be added would be equal to 8 times the original amount of red circles