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3 years ago

Pls help me solve 3-6

Mathematics

1 answer:

lesya692 [45]3 years ago

5 0

Here, four points are B, C, D and E.
Two lines are BC and DE.
S is the plane that contains points A, B, and C.
T is the plane that contains points A, D, and E.

Hope you could understand.

If you have any query, feel free to ask.

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One member of the debate team is going to be chosen president. each member is equally likely to be chosen. the probability that

inessss [21]

Let
x-------> the probability that a boy is chosen
B------> number of boys in the debate team
G------> number of girls in the debate team

we know that
B+G=20-----> G=20-B-----> equation 1
probability that a boy is chosen=number of boys in the debate team/total of people
so
x=B/20-------> equation 2

the probability that a girl is chosen is 2/3 the probability that a boy is chosen
probability that a girl is chosen=(2/3)*x
probability that a girl is chosen=G/20
(2/3)*x=G/20-----> equation 3
substitute equation 1 in equation 3
(2/3)*x=[20-B]/20----> equation 4

resolve the equations system
x=B/20
(2/3)*x=[20-B]/20

using a graph tool
see the attached figure
the solution is
x=0.6
B=12
G=20-12-----> G=8

number of boys in the debate team is 12
number of girls in the debate team is 8
the probability that a boy is chosen is 0.6 ----> 60%
the probability that a girl is chosen is 0.6*(2/3)----> 0.4---> 40%

the answer is
number of girls in the debate team is 8

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4 years ago

F(x)=9x^2 g(x)= sqrt 12-x/3 (f o g)(-4)

Slav-nsk [51]

$f(x)=9x^2 \\ g(x)=\frac{\sqrt{12-x}}{3} \\$ So,first step is to write $(fog)(-4)) =f[g(-4)] \\$

Now we start from inner paranthesis ,we need to first find value of $g(-4) =\frac{\sqrt{12-(-4)}}{3}\\ =\frac{\sqrt{12+4}}{3}\\
=\frac{\sqrt{16}}{3}\\
=\frac{4}{3}\\
(fog)(-4)) =f[g(-4)] =f(\frac{4}{3}) =9(4/3)^{2} =9*(16/9) =144/9 =16$

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Step-by-step explanation:

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Step-by-step explanation:

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