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2 years ago

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Among 420 randomly selected employees at a company, the mean number of hours of overtime worked per month is 10 hours and the st

andard deviation is 1. 6. What is the margin of error, assuming a 99% confidence level? 4. 12 0. 01 0. 20 20. 5.

2 answers:

kari74 [83]2 years ago

8 0

The margin of error of the random selection is 0.20

The given parameters are:

$n = 420$ --- the sample size

$\sigma = 1.6$ --- the standard deviation

$\bar x = 10$ --- the mean

$\alpha = 99\%$ --- the confidence level.

The margin of error (E) is calculated as follows:

$E = z \times \sqrt{\frac{\sigma^2}{n}}$

So, we have:

$E = z \times \sqrt{\frac{1.6^2}{420}}$

$E = z \times \sqrt{\frac{2.56}{420}}$

The z-value for 99% confidence level is 2.576.

Substitute 2.576 for z

$E = 2.576 \times \sqrt{\frac{2.56}{420}}$

$E = 2.576 \times \sqrt{0.006095}$

Take square roots

$E = 2.576 \times 0.0781$

Multiply

$E = 0.2012$

Approximate

$E = 0.20$

Hence, the margin of error is 0.20

Read more about margin of error at:

brainly.com/question/14396648

Fittoniya [83]2 years ago

7 0

Answer:

0.20

Step-by-step explanation:

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What is the equation of the line that passes through the points (5, 3) and (-3,-1)?

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Answer:

y=1/2x+1/2

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Step-by-step explanation:

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First, let's find what m is, the slope of the line...

The slope of a line is a measure of how fast the line "goes up" or "goes down". A large slope means the line goes up or down really fast (a very steep line). Small slopes means the line isn't very steep. A slope of zero means the line has no steepness at all; it is perfectly horizontal.

For lines like these, the slope is always defined as "the change in y over the change in x" or, in equation form:

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Also, let's call the second point you gave, (-3,-1), point #2, so the x and y numbers here will be called x2 and y2. Or, x2=-3 and y2=-1.

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