is there more to the question? because in order find "s" I need to know the question but a majority of the time you would multiply the amount of money the suit cost by the quantity.
Im a math intern.
Answer:
Step-by-step explanation:
Consider the given expression is
![\ln (x\sqrt[3]{x^2+1})](https://tex.z-dn.net/?f=%5Cln%20%28x%5Csqrt%5B3%5D%7Bx%5E2%2B1%7D%29)
We need to rewrite the expression as a sum,difference,or multiple of logarithms.
![[\because \sqrt[n]{x}=x^{\frac{1}{n}}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Csqrt%5Bn%5D%7Bx%7D%3Dx%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D%5D)
Using the properties of logarithm we get
![[\because \ln (ab)=\ln a+\ln b]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Cln%20%28ab%29%3D%5Cln%20a%2B%5Cln%20b%5D)
![[\because \ln (a^b)=b\ln a]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Cln%20%28a%5Eb%29%3Db%5Cln%20a%5D)
Therefore, the simplified form of the given expression is
.
I^2 = (sqrt-1)^2 then the square cancels out so the answer is just
-1
Step-by-step explanation: |x − y| = 1, ok lets play as Alice, my number is y, and the bob number is x.
the condition says that x-y = 1 or x-y = -1.
so, if you know x, then y = 1 +y or y = y - 1. so you have two possibilities.
let's see two cases : first, let's suppose there are no code in the conversation. Then the only way of being shure of your number, is if one of them have the lowest positive number, so the other should have the next one. So if Bob have the number one, Alice knows for shure that she has the 2. Bob knows that she has a 2, but that means he could have a 1 or a 3, but when he sees that Alice is shure about her number, he knows that his number is the 1.
the second case is where the conversation may be a sort of code, saying a phrase x times and changing when x = the number of the other person, in this case, bob will have the 201 and alice the 202.
Answer:
126
Step-by-step explanation:
A line is 180 degrees. I found the degree of the angles in-between 126 and M by subtracting 126 from 180. This means that M is also 126. (Plus the intersecting lines are parallel)