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olasank [31]
3 years ago
8

The Appalachian Trail is about 2,175 miles long.

Mathematics
1 answer:
Nesterboy [21]3 years ago
4 0

Answer:

121 days; 30 full days

Step-by-step explanation:

to find how much days she takes you divide 2175 by 18

2175 / 18 is 120.833333

it will take her at least 121 days because you need to round up

the last portion of the hike would be a quarter of the hike

you would divide the final time by 4 and that is your answer

121 / 4 is 30.25

you have to round down because .25 is not a full day

she hiked 30 full days

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Use the work shown to find the solutions of the quadratic equation. x2 – x –3/4=0 x2 – x = 3/4
bija089 [108]

Answer:

x = - \frac{1}{2}, x = \frac{3}{2}

Step-by-step explanation:

Given

x² - x - \frac{3}{4} = 0

Multiply through by 4 to clear the fraction

4x² - 4x - 3 = 0

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term

product = 4 × - 3 = - 12 and sum = - 4

The factors are + 2 and - 6

Use these factors to split the x- term

4x² + 2x - 6x - 3 = 0 ( factor the first/second and third/fourth terms )

2x(2x + 1) - 3(2x + 1) = 0 ← factor out (2x + 1) from each term

(2x + 1)(2x - 3) = 0

Equate each factor to zero and solve for x

2x + 1 = 0 ⇒ 2x = - 1 ⇒ x = - \frac{1}{2}

2x - 3 = 0 ⇒ 2x = 3 ⇒ x = \frac{3}{2}

8 0
3 years ago
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Marat540 [252]
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5 0
3 years ago
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Write and graph an equation:
Alexxandr [17]

Answer:

y=29*x

Step-by-step explanation:

This problem is a linear function problem. We need at least two points to solve it. After finding two points we will compute the slope and then us the point-slope formula.

If you put 11 gallons of gasoline in your car it will allow you to drive 319 miles, this means that when x= 11 then, y=319. So the first point is (11,319). For the second point you now that if you have no gallons of gasoline then you won't be able to drive so, the second point is (0,0).

Now that we have to points we are able to compute the slope. The formula for the slope is:

m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}.

this way

m = \frac{0-319}{0-11}.

m = 29.

Now that we have the slope, we can use the point-slope formula to get the equation. The point-slope formula is:

(y-y_{1}) = m(x-x_{1}) (here it doesn't matter which point you use, you will get the same result).

Substituting the point (11,319) and the slope:

(y-319) = 29(x-11)

y-319 = 29x-319

y = 29x

And we finaly get the equation!

6 0
3 years ago
After a long study, tree scientists conclude that a eucalyptus tree will grow at the rate of 0.5 6/ (t+4)3 feet per year, where
kipiarov [429]

Answer:

<h2>a) 0.5367feet</h2><h2>b) 0.5223feet</h2><h2>c) 0.7292feet</h2>

Step-by-step explanation:

Given the rate at which an eucalyptus tree will grow modelled by the equation 0.5+6/(t+4)³ feet per year, where t is the time (in years).

The amount of growth can be gotten by integrating the given rate equation as shown;

\int\limits {0.5 + \frac{6}{(t+4)^{3} }  } \, dt \\= \int\limits {0.5} \, dt + \int\limits\frac{6}{(t+4)^{3} }  } \, dx } \, \\= 0.5t +\int\limits {6u^{-3} } \, du \  where \ u = t+4 \ and\ du = dt\\= 0.5t + 6*\frac{u^{-2} }{-2} + C\\= 0.5t-3u^{-2} +C\\= 0.5t-3(t+4)^{-2} + C

a)  The number of feet that the tree will grow in the second year can be gotten by taking the limit of the integral from  t =1 to t = 2

\int\limits^2_1 {0.5 + \frac{6}{(t+4)^{3} }  } \, dt = [0.5t-3(t+4)^{-2}]^2_1\\= [0.5(2)-3(2+4)^{-2}] - [0.5(1)-3(1+4)^{-2}]\\= [1-3(6)^{-2}] - [0.5-3(5)^{-2}]\\ = [1-\frac{1}{12}] - [0.5-\frac{3}{25} ]\\= \frac{11}{12}-\frac{1}{2}+\frac{3}{25}\\   = 0.9167 - 0.5 + 0.12\\= 0.5367feet

b)  The number of feet that the tree will grow in the third year can be gotten by taking the limit of the integral from  t =2 to t = 3

\int\limits^3_2 {0.5 + \frac{6}{(t+4)^{3} }  } \, dt = [0.5t-3(t+4)^{-2}]^3_2\\= [0.5(3)-3(3+4)^{-2}] - [0.5(2)-3(2+4)^{-2}]\\= [1.5-3(7)^{-2}] - [1-3(6)^{-2}]\\ = [1.5-\frac{3}{49}] - [1-\frac{1}{12} ]\\  = 1.439 - 0.9167\\= 0.5223feet

c) The total number of feet grown during the second year can be gotten by substituting the value of limit from t = 0 to t = 2 into the equation as shown

\int\limits^2_0 {0.5 + \frac{6}{(t+4)^{3} }  } \, dt = [0.5t-3(t+4)^{-2}]^2_0\\= [0.5(2)-3(2+4)^{-2}] - [0.5(0)-3(0+4)^{-2}]\\= [1-3(6)^{-2}] - [0-3(4)^{-2}]\\ = [1-\frac{1}{12}] - [-\frac{3}{16} ]\\= \frac{11}{12}+\frac{3}{16}\\   = 0.9167 - 0.1875\\= 0.7292feet

8 0
3 years ago
1. What operations would you use in order to solve 3x – 4 = 26. Please write the operations in the order you would use them.
alex41 [277]

1. add the 4 to both sides

2. divide both sides by 3

3 0
4 years ago
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