Answer:
30 mph
Step-by-step explanation:
Let d = distance (in miles)
Let t = time (in hours)
Let v = average speed driving <u>to</u> the airport (in mph)
⇒ v + 15 = average speed driving <u>from</u> the airport (in mph)
Using: distance = speed x time

Create two equations for the journey to and from the airport, given that the distance one way is 18 miles:

We are told that the total driving time is 1 hour, so the sum of these expressions equals 1 hour:

Now all we have to do is solve the equation for v:







As v is positive, v = 30 only
So the average speed driving to the airport was 30 mph
(and the average speed driving from the airport was 45 mph)
Well i can't really help you in this since i do not know the cost of each calendar, but if you need the formula.
the cost of one calendar = x
so the total cost would be 200 times x (200x)
Answer:
around 179,560
Step-by-step explanation:
you do the total times .33 and then with that number subtract 268,000 which should give you 179,560
Answer:
4.12
Step-by-step explanation:
its 4.12 mark me brainiless