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Hatshy [7]
3 years ago
12

\begin{aligned} & 2x+7y = 3 \\\\ & x=-4y \end{aligned}

Mathematics
1 answer:
zheka24 [161]3 years ago
4 0

Answer:

x = 12 , y = -3

Step-by-step explanation:

Solve the following system:

{2 x + 7 y = 3 | (equation 1)

x = -4 y | (equation 2)

Express the system in standard form:

{2 x + 7 y = 3 | (equation 1)

x + 4 y = 0 | (equation 2)

Subtract 1/2 × (equation 1) from equation 2:

{2 x + 7 y = 3 | (equation 1)

0 x+y/2 = -3/2 | (equation 2)

Multiply equation 2 by 2:

{2 x + 7 y = 3 | (equation 1)

0 x+y = -3 | (equation 2)

Subtract 7 × (equation 2) from equation 1:

{2 x+0 y = 24 | (equation 1)

0 x+y = -3 | (equation 2)

Divide equation 1 by 2:

{x+0 y = 12 | (equation 1)

0 x+y = -3 | (equation 2)

Collect results:

Answer: {x = 12 , y = -3

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3 years ago
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ryzh [129]

Answer:

25

Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
If h (x) = {(-2,3), (0,4), (1,6), (2, 9)}<br><br> then what set of values represent h-1 (x) ?
vfiekz [6]

Answer:

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Step-by-step explanation:

Given: h(x)=\{(-2,3),(0,4),(1,6),(2,9)\}

To find: h^{-1}(x)

Solution:

A relation is said to be a function if each and every element of the domain has a unique image in the co-domain.

Inverse of a function exist if it is both one to one and onto.

h(x)=\{(-2,3),(0,4),(1,6),(2,9)\}

h^{-1}(x)=\{(3,-2),(4,0),(6,1),(9,2)\}

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Answer:

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