Question

A cylindrical, wooden table top has a density of 0.42 g cm 3 and a mass of 0.25 kg.

Answer 1

The radius of the table top, rounded to 1 dp is 5.6 cm

From the question,

We are to determine the radius of the table top

First, we will determine the volume of the cylindrical wooden table

From the given information

Density = 0.42 g/cm³

Mass = 0.25 kg = 250 g

Using the formula

$Volume = \frac{Mass}{Density}$

∴ $Volume = \frac{250}{0.42}$

Volume = 595.238 cm³

Now, for the radius of the table top

Using the formula for volume of a cylinder

$V = \pi r^{2}h$

Where V is the volume

r is the radius

and h is the height or depth

From the given information

h = 6cm

Putting the parameters into the formula

$595.238 = \pi r^{2} \times 6$

∴ $r^{2} = \frac{595.238}{6\pi }$

$r^{2} =31.57835667$

$r =\sqrt{31.57835667}$

r = 5.6 cm

Hence, the radius of the table top, rounded to 1 dp is 5.6 cm

Learn more here: brainly.com/question/11178104