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Alekssandra [29.7K]
2 years ago
14

What is 90 plus 60 plus 7x-12

Mathematics
1 answer:
il63 [147K]2 years ago
8 0

90+60+ 7x -12 = 7x+138

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Which choices are solutions to the following equations x^2+8x-2=18
Olin [163]

Answer:

-4 ± 2√6

Step-by-step explanation:

Rewritten in standard quadratic form, x^2+8x-2=18 becomes x^2 + 8x - 20 = 0.

Here the quadratic coefficients are a = 1, b = 8 and c = -20 and so the discriminant is b^2 - 4ac, or 8^2 - 4(1)(-20), or 96.

Because the discriminant is positive, we know that this quadratic has two different real roots.  These roots are:

      -b ± √(b² - 4ac)

x = -------------------------

                 2a

which in this case comes out to:

       -8 ± √96          -8 ± 4√6          

x = ------------------ = ------------------- = -4 ± 2√6

             2                        2

4 0
2 years ago
Solve the equation for x. If necessary round to the nearest tenth.<br> x² = 17<br> X=<br> +
Ilya [14]

Answer:

x = 4.1 & x = −4.1

Step-by-step explanation:

x^2 = 17\\

x  =  ±√17

x  =  √17,  −√17

x = 4.1 & x = −4.1

7 0
2 years ago
PLEASE HELP ITS FOR A TEST!!
Mashutka [201]

Answer:

22.5

Step-by-step explanation:

multiply 5 x 7 and add half of 5.

multiply 3 x 7 and add half of 3.

width is 22.5

6 0
3 years ago
Read 2 more answers
Which expression is not equivalent to 6^3/6^6
vovangra [49]

Answer:

C

Step-by-step explanation:

The answer is C

8 0
3 years ago
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Find sin θ and cos θ if tan θ= 1/4 and sin 0&gt;0.
Serga [27]

Answer:

\displaystyle \sin(\theta)= \frac{\sqrt{17}}{17}

\displaystyle \cos(\theta)= \frac{4 \sqrt {17} }{ 17 }

Step-by-step explanation:

We want to find sin(θ) and cos(θ) given that tan(θ) = 1/4 and sin(θ) > 0.

First, since tan(θ) and sin(θ) are both positive, cos(θ) must be positive as well.

Recall that tangent is the ratio of the opposite side to the adjacent side.

Therefore, the hypotenuse is:

h=\sqrt{4^2+1^2}=\sqrt{16+1}=\sqrt{17}

So, with respect to θ, the opposite side is 1, the adjacent is 4, and the hypotenuse is √17.

Then it follows that:

\displaystyle \sin(\theta)=\frac{1}{\sqrt{17}} = \frac{\sqrt{17}}{17}

And that:

\displaystyle \cos(\theta)= \frac{4}{\sqrt{17}} = \frac{4 \sqrt {17} }{ 17 }

5 0
3 years ago
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