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lbvjy [14]
2 years ago
10

Helppppppppp plzzzzzzzzzzz

Mathematics
1 answer:
Leya [2.2K]2 years ago
8 0
The answer is 120.
Needs full space
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A survey of 80 randomly selected companies asked them to report the annual income of their presidents. Assuming that incomes are
Artyom0805 [142]

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The 90% confidence interval estimate of the mean annual income of all company presidents is ($579,545, $590,580).

Step-by-step explanation:

The information provided is:

n=80\\\sigma=30,000\\\bar x=585062.50\\\text{Confidence level} = 90\%

The critical value of <em>z</em> for 90% confidence level is, 1.645.

Compute the 90% confidence interval estimate of the mean annual income of all company presidents as follows:

CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\\\\=585062.50\pm 1.645\times\frac{30000}{\sqrt{80}}\\\\=585062.50\pm5517.50\\\\=(579545, 590580)

Thus, the 90% confidence interval estimate of the mean annual income of all company presidents is ($579,545, $590,580).

This interval implies that there is 90% probability that the true mean annual income of all company presidents is within this interval.

4 0
2 years ago
Can you please help with adjacent angles?
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