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balu736 [363]
2 years ago
8

Number of questions answered by each of the ten people are shown on the dot plot below #HELP​

Mathematics
1 answer:
Vikki [24]2 years ago
3 0
Good luck, i’m not sure what this is but like my comment and i’ll come back to it when i get my notes
You might be interested in
Need help from 12-15 pls ?
Zanzabum
The answer would be -3.
7 0
3 years ago
Which equation represents the given statement "Eight times a number minus 2 equals 33
Ivahew [28]

Answer:

8N-2=33+N

Step-by-step explanation:

4 0
3 years ago
Betsy started a business 2 years ago.She had 8 customers in the first year.She added 18 customers in the second year. Betsy's go
liraira [26]

no because 18x 3 is 54 54 216

i think

6 0
3 years ago
Please help me with these
Alex Ar [27]
When we approach limits, we are finding values that are infinitesimally approaching this x-value. Essentially, we consider the approximate location that this root or limit appears. This is essential when it comes to taking Calculus, and finding the limit or rate of change of a function.

When we are attempting limits questions, there are several tests we attempt first.

1. Evaluate the limit by substituting the value of the x-value as it approaches the value (direct evaluation of a limit)
2. Rearrangement of the function, such that we can evaluate the limit.
3. (TRIGONOMETRIC PROPERTIES)
\lim_{x \to 0} (\frac{sinx}{x}) = 1
\lim_{x \to 0} (\frac{tanx}{x}) = 1
4. Using L'Hopital's Rule for indeterminate limits, such as 0/0, -infinity/infinity, or infinity/infinity.

For example:

1) \lim_{x \to 0}\frac{\sqrt{x} - 5}{x - 25}

We can do this using the first and second method.
<em>Method 1: Direct evaluation:</em>

Substitute x = 0 to the function.
\frac{\sqrt{0} - 5}{0 - 25}
= \frac{-5}{-25}
= \frac{1}{5}

<em>Method 2: Rearranging the function
</em>

We can see that x - 25 can be rewritten as: (√x - 5)(√x + 5)
By rewriting it in this form, the top will cancel with the bottom easily, and our limit comes out the same.

\lim_{x \to 0}\frac{(\sqrt{x} - 5)}{(\sqrt{x} - 5)(\sqrt{x} + 5)}
= \lim_{x \to 0}\frac{1}{(\sqrt{x} + 5)}}
= \frac{1}{5}

Every example works exactly the same way, and by remembering these criteria, every limit question should come out pretty naturally.
8 0
3 years ago
!!! CAN SOMEONE HELP !!! (PLEASE ILL GIVE BRAINLIST)
vladimir1956 [14]

Answer:

120 minutes

Step-by-step explanation:

the total bill was $58 so we have to subtract the $40 monthly bill part to find how much extra money she paid because her call was over 200 minutes

58-40=18

Then divide the $18 by $0.15 since the $18 is the total amount of each time she was charged $0.15 for going 1 minute over 200 minutes

18÷0.15 = 120

120 is te Amount Of minutes she went over her 200 minute limit

6 0
3 years ago
Read 2 more answers
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