The tree and the shadow make a right triangle with the tree height opposite the 68 degree angle:
Choice C
(a^3 - 2a + 5) - (4a^3 - 5a^2 + a - 2)
=a^3 - 2a + 5 - 4a^3 + 5a^2 - a + 2
= -3a^3 + 5a^2 - 3a + 7
OK, so;
BDE and BED are congruent because the opposite sides are both congruent
To find BDE and BED you must subtract 66 degrees from 180 degrees.
You are then left with 114 as the sum of both the angles you need to find
Since they are congruent, all you need to do is divide by two
114/2=57 degrees for both BDE (a) and BED(b)
Now for angle A and C;
This is easy because they are both congruent to the first two!
So basically, all of question four is "57 degrees"
Sadly for number 5 i did not understand the question :"(
For 6 tho;
AC is parallel to DE because angle C is congruent to angle BED
All the others can be ruled out
For 7;
BD is half the length of AE, so:
4x+20=2(3x+5)
4x+20=6x+10
20=2x+10
10=2x
x=5
This means BD is 20 bc
3(5)+5
15+5
20
And AE is 40 bc
20X2=40
or...
4(5)+20
No. Not all radical equations have an extraneous solution. <span>However, squaring both sides of an </span>equation<span> can create </span>extraneous solutions.<span>
hope this helps :)</span>
Answer:
Area of the figure = 109 cm. square
Step-by-step explanation:
The radius of the semi circle is 12 ÷ 2 = 6 cm.
Area of the semi circle = 
The radius of the quarter circle is 6 cm.
Area of the quarter circle = 
The area of the rectangle = 12 × 2 = 24
The area of the figure = 18π + 9π + 24 = 108.78 ≅ 109 cm. square
